To determine the maximum and minimum temperatures at which nitrogen remains a liquid, use the equation |x - (-333.32)| = 12.78, where x is equal to the maximum and minimum temperatures. Using this equation, the maximum temperature is -320.54 degrees Fahrenheit while the minimum is -346.10 degrees Fahrenheit.
Answer: 64
Step-by-step explanation:
If EFGH is a parallelogram, its diagonals bisect each other meaning EJ and JG are congruent.
EJ = JG
4w + 4 = 2w + 18
Subtract 2w from both sides
2w + 4 = 18
Subtract 4 from both sides
2w = 14
Divide both sides by 2
w = 7
EG = EJ + JG
EG = 4w + 4 + 2w + 18
EG = 6w + 22
Now that we know what 'w' is, we can substitute it for 7
EG = 6 (7) + 22
EG = 42 + 22 = 64
The measure of EG is 64.
Hope that helped!
Answer:$4669
Step-by-step explanation:
175x19=3325+5(4)=3345
1300+6(4)=1324
Answer:
The minimum sample size needed for use of the normal approximation is 50.
Step-by-step explanation:
Suitability of the normal distribution:
In a binomial distribution with parameters n and p, the normal approximation is suitable is:
np >= 5
n(1-p) >= 5
In this question, we have that:
p = 0.9
Since p > 0.5, it means that np > n(1-p). So we have that:
The minimum sample size needed for use of the normal approximation is 50.
Answer:
Yes
Step-by-step explanation:
Permutation :
nPr = n! ÷ (n - r)!
nCr = n! ÷ (n-r)!r!
11 objects taken 3 at a time :
11P3 = 11! ÷ (11 - 3)!
11P3 = 11! / 8!
11P3 = (11 * 10 * 9 )
11P3 = 990
Dividing by 3!
3! = 3*2*1 = 6
= 990 / 6
= 165
For combination :
11C3 = 11! ÷ 8!3!
11C3 = (11 * 10 * 9) / (3 * 2 * 1)
11C3 = 990 / 6
11C3
