Answer:
Its simple.
Step-by-step explanation:
Add Jerome to the 78 and then 1/4 of molly to get your answer.
Answer:
B
Step-by-step explanation:
Answer:
Not a right triangle
Step-by-step explanation:
We can figure out if it is a right triangle or not by using the pythagorean theorem.
a^2 + b^2 = c^2
In this case a and b are 16 and 18
In order for it to be a right triangle, c has to equal 34, in this problem.
16^2 + 18^2 = c^2
= 580^2
=
= 24.0832
Since 24.0832 does not equal 34, this is not a right triangle
Answer:
16 times
Step-by-step explanation:
![\textsf{Volume of a cone}=\sf \dfrac{1}{3} \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}](https://tex.z-dn.net/?f=%5Ctextsf%7BVolume%20of%20a%20cone%7D%3D%5Csf%20%5Cdfrac%7B1%7D%7B3%7D%20%5Cpi%20r%5E2%20h%20%5Cquad%5Ctextsf%7B%28where%20r%20is%20the%20radius%20and%20h%20is%20the%20height%29%7D)
If only the radius is changed, the change in volume will be proportionate to the multiplicative factor squared.
![\sf \implies Volume =\dfrac{1}{3} \pi (ar)^2h=\dfrac{1}{3} \pi (a^2)r^2h](https://tex.z-dn.net/?f=%5Csf%20%5Cimplies%20Volume%20%3D%5Cdfrac%7B1%7D%7B3%7D%20%5Cpi%20%28ar%29%5E2h%3D%5Cdfrac%7B1%7D%7B3%7D%20%5Cpi%20%28a%5E2%29r%5E2h)
Therefore, if the cone is quadrupled (multiplied by 4), the volume of the larger cone will be 4² times greater than the volume of the smaller cone, so <u>16 times greater </u>than the smaller cone.
<h3><u>Proof</u></h3>
Given:
Substituting the given values into the formula:
![\sf \implies Volume =\dfrac{1}{3} \pi (6)^2(9)=108 \pi \: \:cubic\:units](https://tex.z-dn.net/?f=%5Csf%20%5Cimplies%20Volume%20%3D%5Cdfrac%7B1%7D%7B3%7D%20%5Cpi%20%286%29%5E2%289%29%3D108%20%5Cpi%20%5C%3A%20%5C%3Acubic%5C%3Aunits)
If the radius is quadrupled:
- radius = 6 × 4 = 24
- height = 9
Substituting the new given values into the formula:
![\sf \implies Volume =\dfrac{1}{3} \pi (24)^2(9)=1728 \pi \: \:cubic\:units](https://tex.z-dn.net/?f=%5Csf%20%5Cimplies%20Volume%20%3D%5Cdfrac%7B1%7D%7B3%7D%20%5Cpi%20%2824%29%5E2%289%29%3D1728%20%5Cpi%20%5C%3A%20%5C%3Acubic%5C%3Aunits)
To find the number of times greater the volume of the large cone is than the volume of the smaller cone, divide their volumes:
![\sf \implies \dfrac{V_{large}}{V_{small}}=\dfrac{1728\pi}{108\pi}=16](https://tex.z-dn.net/?f=%5Csf%20%5Cimplies%20%5Cdfrac%7BV_%7Blarge%7D%7D%7BV_%7Bsmall%7D%7D%3D%5Cdfrac%7B1728%5Cpi%7D%7B108%5Cpi%7D%3D16)
So the volume of the larger cone is <u>16 times greater</u> than the volume of the smaller cone.
Answer:
x=5
Step-by-step explanation:
pls heart and give brainliest