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victus00 [196]
3 years ago
15

Bill green, a storm-door salesman, sold $5000 worth of doors and received a commission of $400. What was his rate of commission?

Mathematics
1 answer:
fiasKO [112]3 years ago
3 0
400/5000 = 4/50 = 8/100 = 0.08 = 8%
A: 8%
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What is the ratio as a fraction in lowest term for $300 to $450 ?
Advocard [28]
Just divide 300 by 450, to get 0.66667, which can be expressed as a fraction by 2/3
5 0
3 years ago
Memory module consists of 9 chips. The device is designed with redundancy so that it works even if one of its chips is defective
soldier1979 [14.2K]

Answer:

a) P[C]=p^n

b) P[M]=p^{8n}(9-8p^n)

c) n=62

d) n=138

Step-by-step explanation:

Note: "Each chip contains n transistors"

a) A chip needs all n transistor working to function correctly. If p is the probability that a transistor is working ok, then:

P[C]=p^n

b) The memory module works with when even one of the chips is defective. It means it works either if 8 chips or 9 chips are ok. The probability of the chips failing is independent of each other.

We can calculate this as a binomial distribution problem, with n=9 and k≥8:

P[M]=P[C_9]+P[C_8]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)\\\\P[M]=p^{8n}(p^{n}+9(1-p^n))\\\\P[M]=p^{8n}(9-8p^n)

c)

P[M]=(0.999)^{8n}(9-8(0.999)^n)=0.9

This equation was solved graphically and the result is that the maximum number of chips to have a reliability of the memory module equal or bigger than 0.9 is 62 transistors per chip. See picture attached.

d) If the memoty module tolerates 2 defective chips:

P[M]=P[C_9]+P[C_8]+P[C_7]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1+\binom{9}{7}P[C]^7(1-P[C])^2\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])+36P[C]^7(1-P[C])^2\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)+36p^{7n}(1-p^n)^2

We again calculate numerically and graphically and determine that the maximum number of transistor per chip in this conditions is n=138. See graph attached.

6 0
3 years ago
The graph of f(x)=ax^2 is narrower than the graph of g(x)=dx^2 when a<d
Lynna [10]

Answer:

Step-by-step explanation:

as given in question that a > 0 so

if we put a=1

we get g(x) = f(x)

now put a =2

we get

g(x) = 2 f(x)

here we can see that g(x) would always be greater than or equals to f(x)

so we can say that the graph of g(x) will never be narrower than graph of g(x)

4 0
3 years ago
20% of what number is 7?
ValentinkaMS [17]
Answer: 35
Just took a test on this
8 0
3 years ago
Read 2 more answers
PLEASEE HELP!!<br><br> What is the value of x?<br><br> Enter your answer in the box
madreJ [45]
First we need to figure out how long YK is and the best way to do this is to set up a proportion

34         x
----- = ------
95.2      168

then cross multiply and divide

34 times 168=5712/95.2=60

then add the two parts of the line

60+34=94

X is 94 cm

I hope I've helped!
3 0
3 years ago
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