A population of insects doubles every month. this particular population started out with 20 insects
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The student's friend watch 1.5 movies every week.
Data provided to us {2, 14, 1, 2, 0, 1, 0, 2}.
Number of data values = 8
Sorted or rearranged data {0, 0, 1, 1, 2, 2, 2, 14}
Median of the data provided;
Median is the mid point value of the data provided to us, but as in this case there are 8 data provided (even number of data), we will take the average of the 2 mid values of the data.
Mid Values = 1 and 2
Mean of the data provided;
As we know, The data values provided are 0, 1 and 2, and there is 14 as well in the data which is the maximum value in the data provided to us but the value is far from the other data values provided to us. Therefore, the data value 14 is considered to be an outlier.
An outlier is the maximum value that increases the mean, which makes it larger than it should be.
If we were to compute the mean without the outlier,
Now, we have understood that the mean is sensitive to outlier can be easily manipulated. thus, mean is not the right option to go for in this case.
Therefore, the median value of 1.5 is the right option.
Hence, the student's friend watch 1.5 movies every week.
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