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4 years ago

A population of insects doubles every month. this particular population started out with 20 insects

1 answer:

8 0

Start with 20
After 1 month, 20 * 2 = 20 * 2^1
After 2 months, (20 * 2) * 2 = 20 * 2^2
After 3 months, (20 * 2^2) * 2 = 20 * 2^3
After x months: 20 * 2^x

2x+20, x being a month

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Two lines, A and B, are graphed (Look at the picture):

Snezhnost [94]

Answer:

B. (2,8), because both equations intersect at this point

3 0

3 years ago

Read 2 more answers

Find the first Taylor polynomial T1(x) for f(x)=exp(x) based at b=0:

avanturin [10]

Answer:

f(x) = 1 + x + (x²/2!) + (x³/3!) + ....... = Σ (xⁿ/n!) (Summation from n = 0 to n = ∞)

Step-by-step explanation:

f(x) = eˣ

Expand using first Taylor Polynomial based around b = 0

The Taylor's expansion based around any point b, is given by the infinite series

f(x) = f(b) + xf'(b) + (x²/2!)f"(b) + (x³/3!)f'''(b) + ....= Σ (xⁿfⁿ(b)/n!) (Summation from n = 0 to n = ∞)

Note: f'(x) = (df/dx)

So, expanding f(x) = eˣ based at b=0

f'(x) = eˣ

f"(x) = eˣ

fⁿ(x) = eˣ

And e⁰ = 1

f(x) = 1 + x + (x²/2!) + (x³/3!) + ....... = Σ (xⁿ/n!) (Summation from n = 0 to n = ∞)

6 0

4 years ago

HURRY DONT HAVE MUCH TIMEEE ASAP NEED THIS DONE

nlexa [21]

It is the third one that is the answer

8 0

4 years ago

If OQ and RT are parallel lines and mZRSP = 55°, what is mZQPS?

bogdanovich [222]

Answer:

55 degrees

Step-by-step explanation:

Angles RSP and QPS are Alternate Interior Angles. Given that OQ and RT are parallel, alternate interior angles are always congruent, meaning they have the same measure.

So if angle RSP is 55 degrees and it is congruent to angle QPS, then angle QPS is 55 degrees.

5 0

3 years ago

In the video, the water level was 15 milliliters before adding the chain, and 20 milliliters after adding the chain. When I weig

mr_godi [17]

Answer:

39.7%

Explanation:

1. First find the density of your chain

Density = mass / volume

Volume = displaced water volume

= Volume of Final level of water - initial level of water

= 20 ml - 15 ml = 5 ml

Mass = 66.7 g

Density = 66.7g / 5 ml = 13.34 g/ml

2. Second, write the denisty of the chain as the weighted average of the densities of the other metals:

Mass of gold × density of gold + mass of other metals × density of other metals, all divided by the mass of the chain.

Calling x the amount of gold, then the amount of other metals is 66.7 - x:

$\dfrac{19.3\cdot x+9.7\cdot (66.7-x)}{66.7}=13.34$

$19.3x+635.66-9.7x=889.778$

$9.6x=254.118\\\\x=26.47$

Then, there are 26.47 grams of gold in 66.7 grams of chain, which yields a percentage of:

(26.47 / 66.7) × 100 = 39.7%

7 0

3 years ago