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4 years ago

Someone plzzz explain this to me and tell me the answer thanks

Mathematics

2 answers:

kirill115 [55]4 years ago

6 0

What you do is stack the fractions and subtract 9-3 and you get 6 and bring down the 8 and subtract 5-3 and you get 6 6/8

Svet_ta [14]4 years ago

6 0

I'm hoping you meant both problems

2) 6 2/8 or simplified 6 1/4

6) 3 1/2

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Write the expression for the following the product of five and two ,added to seven. PLS HELP ME

netineya [11]

Answer:

5 times 2 + 7

Step-by-step explanation:

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3 years ago

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Dan drank 7/8 of a bottle of

Anika [276]

Answer:

Dan drank 1 3/8 ths of the bottle of water

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3 years ago

Sarah is 13 years older than Mike. The sum of their ages is 37. How old is Sarah and how old is Mike? Enter your answer as on or

Blizzard [7]

Answer:

(24,13)

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3 0

3 years ago

20 people applied for a job. Everyone either has a school certificate or diploma or even both. If 14 have school certificates an

STatiana [176]

Given:

Either has a school certificate or diploma or even both = 20 people

Having school certificates = 14

Having diplomas = 11

To find:

The number of people who have a school certificate only.

Solution:

Let A be the set of people who have school certificates and B be the set of people who have diplomas.

According to the given information, we have

$n(A)=14$

$n(B)=11$

$n(A\cup B)=20$

We know that,

$n(A\cup B)=n(A)+n(B)-n(A\cap B)$

$20=14+11-n(A\cap B)$

$20=25-n(A\cap B)$

Subtract both sides by 25.

$20-25=-n(A\cap B)$

$-5=-n(A\cap B)$

$5=n(A\cap B)$

We need to find the number of people who have a school certificate only, i.e. $n(A\cap B')$ .

$n(A\cap B')=n(A)-n(A\cap B)$

$n(A\cap B')=14-5$

$n(A\cap B')=9$

Therefore, 9 people have a school certificate only.

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3 years ago

6+3x=7-x. pls solve and i will mark you brainliest

ycow [4]

⇛6 + 3x = 7 - x

⇛3x + x = 7 - 6

⇛4x = 1

⇛x = 1/4

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3 years ago

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