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3 years ago

What number is 16% of 44 rounded to the nearest tenth show the work also and thxs

1 answer:

7 0

SOLUTION:

16% of 44 = 44 × 16% OR 44 × 16 / 100 OR 44 × 0.16

16% of 44 = 7.04

16% of 44 = 7.0 ( rounded to the nearest tenth )

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A six-sided die is rolled. What is the probability of landing on a number less than 3? Put our answer in simplest form.

V125BC [204]

Answer:

1/3

Step-by-step explanation:

2/6

1/3

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3 years ago

Read 2 more answers

In the triangle below, the value of a is 12.6.<br><br> True<br><br> False

aev [14]

Answer:

True

Step-by-step explanation:

Formula

Tan(x) = opposite / adjacent

Givens

x = 42

adjacent = 14

opposite = ?

Solution

Tan(42) = opp/14 Find tan(42)

Tan(42) = 0.900404

0.900404 = opp/ 14 Multiply both sides by 14

14 * 0.900404 = opp/14 * 14 Simplify the left

12.6 rounded = opp

a = 12.6

7 0

3 years ago

I need help with 18, 19, & 20

luda_lava [24]

18. 17.9
19. 21.1
20. I cant see the numbers sorry; if the sides are 6, √85 than it should have an angle of 40.6

4 0

3 years ago

Perry currently has $180 dollars and is spending $6 per day. Nick has no money but is earning $8 each day. After how many days w

Elan Coil [88]

12.857 days

Step-by-step explanation:

Since the number of days is passing the same for both Nick and Perry we can assign the unknown value (no. Of days) the same denotation of x

Therefore;

180 – 6x = 0 + 8x

180 = 8x + 6x

180 = 14x

X = 12.857

Learn More:

For more on calculating unknown values check out;

brainly.com/question/10578482

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4 0

3 years ago

A frequency distribution for the class level of students in an introductory statistics course is shown. Two students are randoml

Andrews [41]

Answer: $\dfrac{21}{410}$ .

Step-by-step explanation:

Formula : Probability = $\dfrac{\text{favorable outcomes}}{\text{Total outcomes}}$

From the given frequency distribution for the class level of students in an introductory statistics course, we have

Number of Junior= 12

Number of Senior = 7

Total students = 6+16+12+7 = 41

Probability that the first student obtained is a junior = $\dfrac{12}{41}$

Probability that the the second student obtained is a senior. $=\dfrac{7}{41-1}=\dfrac{7}{40}$

Then, the probability that the first student obtained is a junior and the second a senior would be $\dfrac{12}{41}\times\dfrac{7}{40}=\dfrac{21}{410}$

Hence, the required probability is $\dfrac{21}{410}$ .

8 0

3 years ago