Question

A frequency distribution for the class level of students in an introductory statistics course is shown. Two students are randomly selected without replacement. Complete parts​ (a) through​ (d).
Class
Frequency

Freshman
6
Sophomore
16
Junior
12
Senior
7
a. Determine the probability that the first student obtained is a junior and the second a senior.

Answer 1

Answer: $\dfrac{21}{410}$.

Step-by-step explanation:

Formula : Probability = $\dfrac{\text{favorable outcomes}}{\text{Total outcomes}}$

From the given frequency distribution for the class level of students in an introductory statistics course, we have

Number of Junior= 12

Number of Senior = 7

Total students = 6+16+12+7 = 41

Probability that the first student obtained is a junior = $\dfrac{12}{41}$

Probability that the the second student obtained is a senior. $=\dfrac{7}{41-1}=\dfrac{7}{40}$

Then, the probability that the first student obtained is a junior and the second a senior would be $\dfrac{12}{41}\times\dfrac{7}{40}=\dfrac{21}{410}$

Hence, the required probability is $\dfrac{21}{410}$.