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Gnesinka [82]
3 years ago
7

What is the d value of the following sequence 4.3, 5.6, 6.9, 8.2

Mathematics
1 answer:
Wewaii [24]3 years ago
3 0
You subtract C from B to get 1.3 then you add 1.3 to 8.2 and get 9.5 as your answer.


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A supply schedule is used to show the
erastovalidia [21]

Answer:

the answer is the supply in a given market.

5 0
3 years ago
Read 2 more answers
Outside a​ home, there is aa 44​-key keypad numbered 11 through 44. The correct sixsix​-digit code will open the garage door. Th
olya-2409 [2.1K]

Answer:

a) 4,096

b) 0.000244

Step-by-step explanation:

a)  

By the Fundamental rule of counting, there are

4*4*4*4*4*4 = 4,096  

ways of forming six-digit arrangements where each position has 4 possibilities (1 to 4)

b)

The probability of entering the correct code on the first try, assuming that the owner does not remember the code is  

1/4096 = 0.000244

5 0
3 years ago
Find the sum of 80/100 and 20/100
ololo11 [35]

We have the same denominator. Therefore:

\dfrac{80}{100}+\dfrac{20}{100}=\dfrac{80+20}{100}=\dfrac{100}{100}=1

7 0
3 years ago
Read 2 more answers
What is the slope of the line described by the data in the table below?
deff fn [24]

Answer:

D

Step-by-step explanation:

General Equation: y = mx + b

You need two pieces of data to solve this.

When x = 1, y = 8

8 = 1x + b

When x = -1, y = 3

3 = - x + b

==================

8 = x + b

3 = -x + b     If we add we get b so let's add.

11 =2b          Divide by 2

11/2 = b

==================

y = mx + b

y = mx + 11/2      Now we can solve for m

3 = -m + 11/2      Subtract 11/2

3 - 11/2 = - m

- 2  1/2 = -m        multiply by - 1

2  1/2 = m

m = 5/2

The answer is D

8 0
3 years ago
Read 2 more answers
Assume that 12 people, including the husband and wife pair, apply for 4 sales positions. People are hired at random.
Iteru [2.4K]

brainly.com/question/5218999


The formula C(n, r)= \frac{n!}{r!(n-r)!}, where r! is 1*2*3*...r

is the formula which gives us the total number of ways of forming groups of r objects, out of n objects.

for example, given 10 objects, there are C(10,6) ways of forming groups of 6, out of the 10 objects.

-----------------------------------------------------------------------------------------------


Selecting 4 people out of 12 can be done in :

\displaystyle{C(12, 4)= \frac{12!}{4!8!}= \frac{12\cdot11\cdot10\cdot9\cdot8!}{4!8!}= \frac{12\cdot11\cdot10\cdot9}{4!}=11\cdot5\cdot9= 495       many ways.


All the possible groups of 4 people, where the husband and wife are included, can be done in C(10, 2) many ways, since we only calculate the possible choices of 2 out of 10 people, to complete the groups of 4.


\displaystyle{ C(10, 2)= \frac{10!}{2!8!}= \frac{10\cdot9}{2}=45


Thus, the 

probability that both the husband and wife are hired is 45/495=0.09


Part 2)

The probability that one is hired and the other is not = 

P(husband hired, wife not hired) + P(wife hired, husband not hired)

these 2 are clearly equal, so it is enough to calculate one.


Consider the case : husband hired, wife not hired.

assuming the husband is hired, we have to calculate the possible groups of 3 that can be formed from 11-1 (the wife)=10 people.

this is 

\displaystyle{ C(10, 3)= \frac{10!}{3!7!}= \frac{10 \cdot9 \cdot8}{3\cdot2}=10\cdot3\cdot4=120


thus, 


P(husband hired, wife not hired)=120/495=0.24


thus, 

The probability that one is hired and the other is not = 

P(husband hired, wife not hired) + P(wife hired, husband not hired) =

0.24+0.24=0.48



Answer:


A) 0.09


B) 0.48

4 0
3 years ago
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