Answer:
0.15-0.75p? YES
-0.45-0.6+0.75P? NO
-3(-0.05+0.25p)? YES
-3(0.15)+(-3)(0.2)+(-3)(0.25p)? NO
Step-by-step explanation:
-3(0.15-0.2+0.25p)
=-0.45+0.6-0.75p
=0.15-0.75p
1. 0.15-0.75p=0.15-0.75p? YES
2. -0.45-0.6+0.75P=0.15-0.75p?
-1.05+0.75p=0.15-0.75p? NO
3. -3(-0.05+0.25p)=0.15-0.75p?
0.15-0.75=0.15-0.75p? YES
4. -3(0.15)+(-3)(0.2)+(-3)(0.25p)=0.15-0.75p?
-0.45-0.6-0.75p=0.15-0.75p?
-1.05-0.75p=0.15-0.75p? NO
Answer:
The value of a + 2z/ 2 in terms of a is (3a+4)/2
Step-by-step explanation:
least of 3 consecutive integers is a, and the greatest is z
if a is the least one
we know that integers differ by value of 1.
example -2, -1, 0, 1,2
they all differ by
then next consecutive integer will be a+1
third integer will be second integer +1 = a+1 + 1 = a+2
Thus, 3 consecutive integer
a , a+1, a+2
but given that greatest is z
thus, a+2 is greatest and hence
a+2 = z
we have to find value of a + 2z/ 2 in terms of a
a + 2z/ 2 = a + 2(a+2)/2 = (a+ 2a +4)/2 = (3a+4)/2.
The value of a + 2z/ 2 in terms of a is (3a+4)/2
Answer:
4sqrt(2) cm
Step-by-step explanation:
a^2 + b^2 = c^2
4^2 + 4^2 = c^2
32 = c^2
sqrt(32) = c
c = 4sqrt(2)
Answer:
<em>A.) There is a 3.4% chance that a random sample of 50 expectant mothers will have a mean age of 26.5 years old or greater if the mean age for a first time mother is 26 years old.</em>
Step-by-step explanation:
The mean age for a first time mother is assumed 26 years old (null hypothesis) and <em>p-value</em> of the sample mean (26.5 years ) is found as 0.034.
This is the probability of having first time mother mean age 26.5 or greater <em>under the assumption of null hypothesis. </em>
Answer:
h = 0.748
Step-by-step explanation:
This is the correct answer, further proof in the file attached.
