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Vika [28.1K]
3 years ago
12

Work out the value of (6.31×10⁵)+(2.6×10⁴) give your answer in standard form​

Mathematics
2 answers:
timurjin [86]3 years ago
8 0
10 4 x (6.31 x 10 + 2.6) = 10 4 x 65.7 = 6.57 x 10 4
lidiya [134]3 years ago
7 0

Answer:

bellow

Step-by-step explanation:

10^{4}*(6.31*10+2.6) = 10^{4}*65.7= 6.57* 10^{5}

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Need help to understand this question thank you :)
Novosadov [1.4K]
Complementary angles add up to equal 90 degrees. Knowing this, you can subtract 68 from 90. 90-68=22.

Hope this helps.
8 0
3 years ago
What does 90-3x equal
Nikolay [14]
90-3x=?

Get x to one side 

So minus 90 from each side

-3x=-90

-90÷-3=30

Answer: x=30 

6 0
3 years ago
A random sample of 102 full-grown lobsters had a mean weight of 16 ounces and a standard deviation of 3.4 ounces. Construct a 98
pshichka [43]

Answer:

The best point estimate for a confidence interval estimating the population μ is 16 ounces.

The 98 percent confidence interval for the population mean μ is between 15.21 ounces and 16.79 ounces.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The best point estimate for a confidence interval estimating the population μ is

The sample mean, so 16 ounces.

T interval

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 102 - 1 = 101

98% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 101 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.98}{2} = 0.99. So we have T = 2.36

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.36\frac{3.4}{\sqrt{102}} = 0.79

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 16 - 0.79 = 15.21 ounces

The upper end of the interval is the sample mean added to M. So it is 16 + 0.79 = 16.79 ounces

The 98 percent confidence interval for the population mean μ is between 15.21 ounces and 16.79 ounces.

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3 years ago
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Delicious77 [7]
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