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3 years ago

Between which two square roots of integers would you find pi?

Mathematics

1 answer:

Aneli [31]3 years ago

6 0

Since 3 < pi < 4,
√9 < pi √16 

In fact, since pi^2 = 9.86, 

√9 < pi < √10

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In Bill the Boring dryer there are black shirts, gray shirts, black sweaters, and gray sweaters. Bill is going to take one of th

Ostrovityanka [42]

Answer:

Shirt probability: 100%

Black probability 50%

Step-by-step explanation:

Hope this helps! Brainliest would be much appreciated! Have a great day! :)

7 0

2 years ago

Which of the following is NOT true about similar figures?

Lesechka [4]

Answer:

b. Similar figures have always the same size. is a false statement.

since size differs.

4 0

3 years ago

Read 2 more answers

What’s the differential equation of

worty [1.4K]

Answer:

$y=\frac{1}{x^{2}-6x+13 }$

Step-by-step explanation:

We have given,

$\frac{dy}{dx}=y^{2}(6-2x)$

and initial condition $x=3,\ y=\frac{1}{4}$

Now,

$\frac{dy}{dx}=y^{2}(6-2x)$

Rearranging the variables, we get

$\frac{dy}{y^{2} }=(6-2x).dx$

Applying integration both sides, we get

$\int\ {\frac{dy}{y^{2} } } \,=\int\ {(6-2x).} \, dx$

⇒ $\frac{-1}{y} =6x-\frac{2x^{2} }{2}$

⇒ $\frac{-1}{y}=6x-x^{2} +C$

Putting the initial condition (i.e., $x=3,\ y=\frac{1}{4}$ ), we get

⇒ $-4=6\times3-(3)^{2}+C$

⇒ $-4=18-9+C$

∴ $C=-13$

We have, $\frac{-1}{y}=6x-x^{2} +C$

now putting the value of $C$ in above equation, we get

⇒ $\frac{-1}{y}=6x-x^{2} -13$

⇒ $\frac{1}{y}=-6x+x^{2} +13$

$y=\frac{1}{x^{2}-6x+13 }$

5 0

3 years ago

Help please asap thanks

Ymorist [56]

Answer:

x = 8

Step-by-step explanation:

7 0

3 years ago

What is the solution to this equation? 4(x - 6) = 2x + 12

Shkiper50 [21]

X is equal to nine :))

6 0

3 years ago

Read 2 more answers