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statuscvo [17]
3 years ago
10

Beginning with an integer $n,$ Jake goes through the following steps: $\bullet$ 1. Take the reciprocal of the starting number. $

\bullet$ 2. Double the number obtained in Step 1. $\bullet$ 3. Take the reciprocal of the number obtained in Step 2. At the end of the third step, Jake ends up with the number $16.$ What number did Jake start with?
Mathematics
2 answers:
fgiga [73]3 years ago
6 0

See https://web2.0calc.com/questions/need-help-with-problem_1.

evablogger [386]3 years ago
4 0

Answer: n= 32

Jakes started with 32

Step-by-step explanation:

Let n represent the initial integer.

Step 1: take the reciprocal.

Reciprocal of n = 1/n

Step 2: double the number obtained in step 1

= 2×1/n = 2/n

Step 3: take the reciprocal of the number obtained in step 2.

Reciprocal of 2/n = n/2

Since he ended up with 16

n/2 = 16

n = 2×16 = 32

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2 years ago
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Answer:

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5 0
3 years ago
1. The sum of a two-digits number is 13. The tens digit is 8 less than twice the units digit. What is the number?
alexgriva [62]

Answer:

<u>The number is 67</u>

Step-by-step explanation:

<u>Equations</u>

Let's consider the number 83. The tens digit is 8 and the unit digit is 3. Note the tens digit's addition to the number is 80, and the unit's addition is 3. This means the tens digit adds 10 times its value, that is, 83 = 8*10 + 3.

Now, let's consider the number ab, where a is the tens digit, and b is the unit digit. It follows that

Number=10*a+b

The question gives us two conditions:

1) The sum of a two-digits number is 13.

2) The tens digit is 8 less than twice the units digit.

The first condition can be expressed as:

a + b = 13                     [1]

And the second condition can be written as:

a = 2b-8                      [2]

Replacing [2] into [1], we have:

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Substituting into [2]:

a = 2*(7) - 8 = 6

Thus, the number is 67

3 0
3 years ago
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