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cricket20 [7]
3 years ago
14

A recent survey by the American Cancer Society shows that the probability that someone is a smoker is P(S) = 0.19. It has also d

etermined that the probability that someone has lung cancer, given that he or she is a smoker, is P(LC|S) = 0.158. What is the probability (rounded to the nearest hundredth) that a random person is a smoker and has lung cancer P(S ∩ LC)? 0.03 0.83 0.35 0.02
Mathematics
1 answer:
nekit [7.7K]3 years ago
8 0
0.19*0.158=0.03002 -------> 0.03
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