Question

A recent survey by the American Cancer Society shows that the probability that someone is a smoker is P(S) = 0.19. It has also determined that the probability that someone has lung cancer, given that he or she is a smoker, is P(LC|S) = 0.158. What is the probability (rounded to the nearest hundredth) that a random person is a smoker and has lung cancer P(S ∩ LC)? 0.03 0.83 0.35 0.02

Answer 1

0.19*0.158=0.03002 -------> 0.03