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bezimeni [28]
3 years ago
15

Michelle jumps from a plane at an altitude of 1000 m. After 10 seconds her parachute opens. The graph shows the relationship bet

ween the distance traveled and time. How long does it take for her to be half way between the plane and the ground? (1 point)
Continuous graph with the y axis labeled Distance (m) and the x axis labeled Time, min. The function consists of 3 lines, the first is almost vertical with a positive slope connecting the points 0,0, to approximately 1 of 6, 250. From that point the second line connects to the first and passes through the points 1,500, 2,800 and 2 1 over 3, 1000. From that point the function is horizontal.

a
40 s

b
1 min

c
1 min 20 s

d
1 min 40 s

Mathematics
1 answer:
Delvig [45]3 years ago
6 0

Answer:

B

Step-by-step explanation:

If you look at the graph/chart, it starts at 1,000, so half of that is 500, so you go down to 500, and go straight down to see the number of time under it (In this case, is 1 minute) so you know it is one minute

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Evaluate the following pic
GREYUIT [131]

Answer:

1) \sqrt{1225}+\sqrt{1024}=67

2)  \sqrt[3]{-1331}=-11

3) Evaluating 2:p :: p:8 we get p=\pm 4

4) x^3+y^2+z \ when \ x=3, y=-2, x=-6 \ we \ get \ \mathbf{25}

5) \frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}=-6

Step-by-step explanation:

1) \sqrt{1225}+\sqrt{1024}

Prime factors of 1225 : 5x5x7x7

Prime factors of 1024: 2x2x2x2x2x2x2x2x2x2

\sqrt{1225}+\sqrt{1024}\\=\sqrt{5\times5\times7\times7}+\sqrt{2\times2\times2\times2\times2\times2\times2\times2\times2\times2}\\=\sqrt{5^2\times7^2}+\sqrt{2^2\times2^2\times2^2\times2^2\times2^2}\\=5\times7+(2\times2\times2\times2\times2)\\=35+32\\=67

\sqrt{1225}+\sqrt{1024}=67

2) \sqrt[3]{-1331}

We know that \sqrt[n]{-x}=-\sqrt[n]{x} \ ( \ if \ n \ is \ odd)

Applying radical rule:

\sqrt[3]{-1331}\\=-\sqrt[3]{1331} \\=-\sqrt[3]{11\times\11\times11}\\=-\sqrt[3]{11^3} \\Using \ \sqrt[n]{x^n}=x \\=-11

So, \sqrt[3]{-1331}=-11

3) 2:p :: p:8

It can be written as:

p*p=2*8\\p^2=16\\Taking \ square \ root \ on \ both \ sides\\\sqrt{p^2}=\sqrt{16}\\p=\pm 4

Evaluating 2:p :: p:8 we get p=\pm 4

4) x^3+y^2+z \ when \ x=3, y=-2, x=-6

Put value of x, y and z in equation and solve:

x^3+y^2+z \\=(3)^3+(-2)^2+(-6)\\=27+4-6\\=25

So, x^3+y^2+z \ when \ x=3, y=-2, x=-6 \ we \ get \ \mathbf{25}

5) \frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}

We know (-a)^n = (a)^n when n is even and (-a)^n = (-a)^n when n is odd

\frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}\\\\=\frac{1296\times-8\times 27}{46656}\\\\=\frac{-279936}{46656} \\\\=-6

So, \frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}=-6

8 0
3 years ago
Fred is making a bouquet of carnations and roses. The carnations cost $5.25 in all. The roses cost $1.68 each. How many roses di
Juliette [100K]

Answer:

Fred used <u>8 roses</u> to make the bouquet.

Step-by-step explanation:

Let 'x' roses be used to make a bouquet.

Given:

Cost of carnations = $5.25

Cost of 1 rose = $1.68

Total cost of the bouquet = $18.69

Cost of 1 rose = $1.68

Therefore, using unitary method, the cost of 'x' roses is given as:

Cost of 'x' roses = 1.68x

<em><u>Now, as per question:</u></em>

Cost of carnations + Cost of 'x' roses = Total cost of the bouquet

5.25+1.68x=18.69\\\\1.68x=18.69-5.25\\\\1.68x=13.44\\\\x=\frac{13.44}{1.68}\\\\x=8

Therefore, Fred used 8 roses to make the bouquet.

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I don't understand how to solve this problem
bazaltina [42]
What kind of sh*t are you learning man?
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What is 369.4 in standard form
makvit [3.9K]

Answer:3.694x10^2

Step-by-step explanation:

3 0
4 years ago
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likoan [24]
Plug in the possible answers into the equation and solve for x. x=0
7 0
4 years ago
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