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3 years ago

Need answers to question below :) will give crown to the first one to answer

Mathematics

2 answers:

coldgirl [10]3 years ago

6 0

Sorry but to many questions and only 5 points so hey only get one answer…. #2 is (2,12) and (2,-4)

Rudik [331]3 years ago

4 0

Unfortunately I'm unable to understand

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Will mark brainlest please help!!!! all the choices are the same

Bumek [7]

Going from top to bottom.

The first graph is labeled x≤−5.

The second graph is labeled x>5.

The third graph is labeled x≥−5.

The fourth graph is labeled x>5.

You can find All of these by graphing each inequality.

7 0

3 years ago

A hiker standing at point G wants to estimate the distance across the lake to point H, which is directly north of her location.

riadik2000 [5.3K]

Answer:

Step-by-step explanation:

The diagram is attached.

Looking at the diagram, we want the side "opposite" of the angle given and the side "adjacent" is given.

Which ratio relates opposite and adjacent? It is Tan.

We can use trigonometry and tan ratio to solve for the distance "x":

$Tan(84)=\frac{x}{650}\\x=Tan(84)*650\\x=6184.4$

D is the correct answer.

5 0

3 years ago

Which is an example of an expression? O 3,2 – 4. O a = 144 0 10 = 2.5 O 2 < 52

cluponka [151]

Answer:

2 - 4

Step-by-step explanation:

no equal sign

4 0

3 years ago

A pair of skis were $275 but were on sale for $195. What percent reduction is this?

Stels [109]

$275*x%=195

It will be a 29% reduction. But it will not have the exact cost of $195

7 0

4 years ago

The fish population of a lake is decreasing each year. A study is conducted. But, unfortunately some data was lost. The research

Solnce55 [7]

Answer:

$F(t) = 18000(0.6666)^{t}$

Step-by-step explanation:

The fish population after t years can be modeled by the following equation:

$F(t) = F(0)(1-r)^{t}$

In which F(0) is the initial population and r is the constant rate of decay.

Year one the fish population was 18000

This means that $F(0) = 18000$

In year three the fish population was 8000 fish.

Two years later, so $F(2) = 8000$

$F(t) = F(0)(1-r)^{t}$

$8000 = 18000(1-r)^{2}$

$(1-r)^{2} = 0.4444$

$\sqrt{(1-r)^{2}} = \sqrt{0.4444}$

$1 - r = 0.6666$

$r = 0.3334$

$F(t) = 18000(0.6666)^{t}$

4 0

4 years ago