Answer:
The value of X is more than equal to -1.83.
Step-by-step explanation:
We need to find the correct representation of the inequality 'minus 32X -5 less than 52 minus X'
LHS of the inequality will be : -32x-5
RHS of the inequality will be : (52-X)
So,

Adding X both sides

Adding 5 to both sides,

Dividing both sides by -31.

So, the value of X is more than equal to -1.83.
The first thing we will do is define an equilateral triangle:
In geometry, an equilateral triangle is a regular polygon with three equal sides. In traditional Euclidean geometry, equilateral triangles are also equiangular, that is, the three internal angles are also congruent to each other, each angle with a value of 60 °
Every equilateral triangle consists of three equal sides and three congruent angles.
Therefore, there can be a triangle with three equal sides (5 centimeters in this case).
Answer:
1) one
Answer:
Hii i just know the 4 and 5 one
Step-by-step explanation:
4 one is exterior
5 one is included angle
You can just do the inverse operation. 39 divied by 10 = 3.9
so 3.9 *10 =39
hope it helped
Observe the given data distribution table carefully.
The 5th class interval is given as,

The upper limit (UL) and lower limit (LL) of this interval are,

Thus, the upper-class limit of this 5th class is 17.4.