2 years ago

In the figure, Δ ABC Δ XYZ. What is the perimeter of ΔABC? Show your work.

1 answer:

slava [35]2 years ago

8 0

Answer:

Step-by-step explanation:

∆ABC~ ∆XYZ

AB= 11 that is half of XY = 22

therefore XZ/2 = AC (base) = 32/2 = 16

and YZ /2 = BC(hypotenuse) = 44/2 = 22

(a= 11, b= 16, c= 22)

perimeter of a triangle

P = a+b+c

P= 11+16+22= 49

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