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Viefleur [7K]
3 years ago
8

The cost of a product has been increasing each year.

Mathematics
1 answer:
andrew-mc [135]3 years ago
3 0

i believe it’s $17 because it looks like it’s an constant graph

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Over the past ten years, the town's population doubled in size. The population is currently 12,000. What was the population ten
Alekssandra [29.7K]
6,000 right? I think
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3 years ago
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What is the distance between the points (5, 1) and (-3,-5)?
Reil [10]

Answer: THIRD OPTION.

Step-by-step explanation:

For this exercise you need to use the formula for calculate the distance between two points. This is:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Given the following points:

(5, 1) and (-3,-5)

You can identify that:

x_2=-3\\x_1=5\\\\y_2=-5\\y_1=1

Knowing these values, the next step is to substitute them into the equation for calculate the distance between two points and then evaluate.

Therefore, the distance between (5, 1) and (-3,-5) is:

d=\sqrt{(-3-5)^2+(-5-1)^2}\\\\d=10

8 0
3 years ago
Ed’s rental charges a flat fee of $5 plus $2 per hour to rent a pair of skates. A. Write an equation to model the cost of rentin
VashaNatasha [74]
The cost equation has a constant rate of change, so this is a line of the form:

y=mx+b, you are told that there is a flat fee of $5 and an hourly rate of $2 so

y=2x+5

The y-intercept (the value of y when x=0) is 5.  The point (0,5) on the line. 
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What is the volume of the square pyramid with base edges 10 in. and height 9 in.?
klemol [59]
The answer is 300.

Hope this helps!
5 0
3 years ago
What is the perimeter of the triangle shown on the coordinate plane, to the nearest tenth of a unit?
Akimi4 [234]

Answer:

25.6 units

Step-by-step explanation: From the figure we can infer that our triangle has vertices A = (-5, 4), B = (1, 4), and C = (3, -4).

First thing we are doing is find the lengths of AB, BC, and AC using the distance formula:

d=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}

where

(x_1,y_1) are the coordinates of the first point

(x_2,y_2) are the coordinates of the second point

- For AB:

d=\sqrt{[1-(-5)]^{2}+(4-4)^2}

d=\sqrt{(1+5)^{2}+(0)^2}

d=\sqrt{(6)^{2}}

d=6

- For BC:

d=\sqrt{(3-1)^{2} +(-4-4)^{2}}

d=\sqrt{(2)^{2} +(-8)^{2}}

d=\sqrt{4+64}

d=\sqrt{68}

d=8.24

- For AC:

d=\sqrt{[3-(-5)]^{2} +(-4-4)^{2}}

d=\sqrt{(3+5)^{2} +(-8)^{2}}

d=\sqrt{(8)^{2} +64}

d=\sqrt{64+64}

d=\sqrt{128}

d=11.31

Next, now that we have our lengths, we can add them to find the perimeter of our triangle:

p=AB+BC+AC

p=6+8.24+11.31

p=25.55

p=25.6

We can conclude that the perimeter of the triangle shown in the figure is 25.6 units.

Read more on Brainly.com - brainly.com/question/12560433#readmore

8 0
3 years ago
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