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Yanka [14]
3 years ago
10

An oxygen tank contained 212 12/3 liters of oxygen before 27 1/3 liters were used. If the tank can hold 240 3/8 liters, how much

space in the tank is unused
Mathematics
1 answer:
lukranit [14]3 years ago
5 0
So, initially   240\frac{3}{8} -212 \frac{12}{3} were empty:

this is :

240  \frac{3}{8} - 212  \frac{12}{3}  = 240  \frac{3}{8} - 212  +4 = 240  \frac{3}{8} - 216= 24  \frac{3}{8}

12/4 is 4 so that's why i substituted it with 4.

now, later 27 1/3 were used so we add this tho the original empty space

 24  \frac{3}{8}+ 27  \frac{1}{3} =  24  \frac{9}{24}+ 27  \frac{8}{24} = 51  \frac{17}{24}


which is the result!





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