The number of ways that the coach can assign the 4 positions to his 16 players would be 43, 680 ways
<h3>How to calculate the permutation</h3>
The formula for permutation is given as;
Permutation = 
n = 16
r =4
Permutation = 
Permutation = 
Permutation = 43, 680 ways
Thus, the number of ways that the coach can assign the 4 positions to his 16 players would be 43, 680 ways
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Answer: the probability that exactly two of the next five people who apply to that university get accepted is 0.23
Step-by-step explanation:
We would number of people that applies for admission at the university and gets accepted. The formula is expressed as
P(x = r) = nCr × p^r × q^(n - r)
Where
x represent the number of successes.
p represents the probability of success.
q = (1 - p) represents the probability of failure.
n represents the number of trials or sample.
From the information given,
p = 0.6
q = 1 - p = 1 - 0.6
q = 0.4
n = 5
the probability that exactly two of the next five people who apply to that university get accepted is
P(x = 2) = 5C2 × 0.6^2 × 0.4^(5 - 2)
P(x = 2) = 10 × 0.36 × 0.064
P(x = 2) = 0.23
<u>Answer-</u>
<em>D. The function has one real zero and two nonreal zeros. The graph of the function intersects the x-axis at exactly one location.</em>
<u>Solution-</u>
The given polynomial is,
The zeros of the polynomials are,
Therefore, this function has only one real zero i.e 1 and two nonreal zeros i.e ±√6i . The graph of the function intersects the x-axis at exactly one location i.e at x = 1
2/5m - 4/5 - 3/5m...combine like terms
-1/5m - 4/5
