Factor x^4+xy^3+x^3+y^3 out completely. Hint: first factor out a monomial.
1 answer:
Answer:
(x + y)(x² - xy + y²)(x + 1)
Step-by-step explanation:
Given
+ xy³ + x³ + y³ ( factor out x from the first 2 terms )
= x(x³ + y³) + 1(x³ + y³) ← factor out (x³ + y³) from each term
= (x³ + y³)(x + 1)
x³ + y³ is a sum of cubes and factors as (x + y)(x² - xy + y²)
Thus
+ xy³ + x³ + y³ = (x + y)(x² - xy + y²)(x + 1)
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Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
