This question is incomplete because it was not written properly
Complete Question
A teacher gave his class two quizzes. 80% of the class passed the first quiz, but only 60% of the class passed both quizzes. What percent of those who passed the first one passed the second quiz? (2 points)
a) 20%
b) 40%
c) 60%
d) 75%
Answer:
d) 75%
Step-by-step explanation:
We would be solving this question using conditional probability.
Let us represent the percentage of those who passed the first quiz as A = 80%
and
Those who passed the first quiz as B = unknown
Those who passed the first and second quiz as A and B = 60%
The formula for conditional probability is given as
P(B|A) = P(A and B) / P(A)
Where,
P(B|A) = the percent of those who passed the first one passed the second
Hence,
P(B|A) = 60/80
= 0.75
In percent form, 0.75 × 100 = 75%
Therefore, from the calculations above, 75% of those who passed the first quiz to also passed the second quiz.
Answer:
89/35 = 2 and 19/35
Step-by-step explanation:
"One rotation" would be the circumference of the wheel, which is
C = 2*pi*r, or (here) C = 2*pi*(8 inches) = 16*pi inches.
1 ft
Convert this to feet: 16*pi inches times ---------------
12 inches
Here "inches" cancels out and you are left with (4/3)pi ft.
So, one rotation of the wheel moves you and your bike forward (4/3)pi ft.
Divide this into 700 feet:
700 ft 2100
------------- = --------- rotations = 525 rotations (answer)
(4/3) pi ft 4
