Answer:
c + d = 400
0.2c + 0.5d = 156
Step-by-step explanation:
Let
c = number of liters of 20% acid solution
d = number of liters of 50% acid solution.
c + d = 400 (1)
0.2c + 0.5d = 400(0.39)
0.2c + 0.5d = 156 (2)
From (1)
c = 400 - d
Substitute c = 400 - d into (2)
0.2c + 0.5d = 156 (2)
0.2(400 - d) + 0.5d = 156
80 - 0.2d + 0.5d = 156
- 0.2d + 0.5d = 156 - 80
0.3d = 76
d = 76/0.3
d = 253.33 liters
Substitute d = 253.33 into (1)
c + d = 400
c + 253.33 = 400
c = 400 - 253.33
c = 146.67 liters
Answer:
a) z = -0.358
b) z = 0.358
Step-by-step explanation:
We are given a standard normal distribution.
a) We have to find the value of z such that the proportion of observations that are less than z in a standard normal distribution is 0.36.
That is,

This value will be calculated with the help of a standard normal table.
From standard normal table we have,

Thus, for z equal to -0.358 the proportion of observations that are less than z in a standard normal distribution is 0.36
b) We have to find the value of z such that 36% of all observations from a standard normal distribution are greater than z.

This value will be calculated with the help of a standard normal table.
Calculation the value from standard normal z table, we have,

Thus, 36% of all observations from a standard normal distribution are greater than z equal to 0.358
Answer:
2
Step-by-step explanation:
60/30 is 2
HOpe this helps :D
PLz mark brainliest if correct :D
Answer:
b = 161, m = 111
Step-by-step explanation:
b + m = 272
m + 50 = b
Substitute
m + 50 + m = 272
2m = 222
m = 111
Plug in for m
b + 111 = 272
b = 161
Answer:
20
Step-by-step explanation:
To find the least number of leafs that each collection must have, we find the L.C.M of both numbers. So L.C.M of 4 and 5.
The prime factors of 4 = 2²
The prime factors of 5 = 5
So L.C.M of 4 and 5 = 2² × 5 = 20
So, the least number of leafs that each collection can have is 20 leafs.