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hodyreva [135]
3 years ago
13

You are running a fuel economy study. One of the cars you find is blue. It can travel 45 1/2 miles on 1 1/4 of gasoline. Another

car is red. It can travel 23 3/5 miles on 4/5 of gasoline. What is the unit rate for miles per gallon for each​ car? Which car could travel the greater distance on 1 gallon of​ gasoline?
Mathematics
1 answer:
Sever21 [200]3 years ago
7 0

Answer:

Nghe

… Thấp thoáng ánh mắt, thấp thoáng ánh mắt

Thấp thoáng ánh mắt, thấp thoáng ánh mắt

Good boy

… Thấp thoáng ánh mắt đôi môi mang theo hương mê say

Em cho anh tan trong miên man quên luôn đi đêm ngày

Chạm nhẹ vội vàng hai ba giây nhưng con tim đâu hay

Bối rối khẽ lên ngôi yêu thương đong đầy thật đầy

… Anh ngẩn ngơ cứ ngỡ

(Đó chỉ là giấc mơ)

Anh ngẩn ngơ cứ ngỡ

(Như đang ngất ngây trong giấc mơ)

Thật ngọt ngào êm dịu đắm chìm

Phút chốc viết tương tư gieo nên thơ

… Có câu ca trong gió hát ngân nga, ru trời mây

Nhẹ nhàng đón ban mai ngang qua trao nụ cười

Nắng đua chen, khoe sắc, vui đùa giữa muôn ngàn hoa

Dịu dàng đến nhân gian âu yếm tâm hồn người

… Hình như chính em

(Cho anh mong chờ)

Hình như chính là em

(Cho anh vấn vương)

Đừng thờ ơ, xin hãy lắng nghe

Và giúp anh trả lời đôi điều còn băn khoăn

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Inveres laplace transform (3s-14)/s^2-4s+8​
Olenka [21]

Complete the square in the denominator.

s^2 - 4s + 8 = (s^2 - 4s + 4) + 4 = (s-2)^2 + 4

Rewrite the given transform as

\dfrac{3s-14}{s^2-4s+8} = \dfrac{3(s-2) - 8}{(s-2)^2+4} = 3\times\dfrac{s-2}{(s-2)^2+2^2} - 4\times\dfrac{2}{(s-2)^2+2^2}

Now take the inverse transform:

L^{-1}_t\left\{3\times\dfrac{s-2}{(s-2)^2+2^2} - 4\times\dfrac{2}{(s-2)^2+2^2}\right\} \\\\ 3L^{-1}_t\left\{\dfrac{s-2}{(s-2)^2+2^2}\right\} - 4L^{-1}_t\left\{\dfrac{2}{(s-2)^2+2^2}\right\} \\\\ 3e^{2t} L^{-1}_t\left\{\dfrac s{s^2+2^2}\right\} - 4e^{2t} L^{-1}_t\left\{\dfrac{2}{s^2+2^2}\right\} \\\\ \boxed{3e^{2t} \cos(2t) - 4e^{2t} \sin(2t)}

5 0
3 years ago
The main show tank has a radius of 70 feet and forms a quarter sphere what is the volume of the quarter sphere shaped tank?
Usimov [2.4K]

Answer:

359333.33\textrm{ }ft^{3}

Step-by-step explanation:

Given:

Radius of spherical tank, r=70\textrm{ ft}

Volume of a quarter of a sphere is given as:

V=\frac{1}{3}\pi r^{3}

Plug in 70 ft for r, \frac{22}{7} for \pi and solve for the volume, V. This gives,

V=\frac{1}{3}\pi r^{3}\\\\ V=\frac{1}{3}\times \frac{22}{7}\times (70)^{3}\\\\ V=359333.33\textrm{ }ft^{3}

Therefore, the volume of the quarter sphere shaped tank is 359333.33\textrm{ }ft^{3}

4 0
4 years ago
Divide £143 in the ratio 2 : 11
OleMash [197]

Answer:

121€

Step-by-step explanation:

;)

6 0
3 years ago
Read 2 more answers
Can someone help me do these it’s really hard
Elena L [17]

Answer:

40 cubes

Step-by-step explanation:

multiply side lengths or the prism by 2, then solve for volume

2.5 * 2 = 5

2 * 2 = 4

1 * 2 = 2

5 * 4 * 2 = 40

4 0
3 years ago
MP bisects ∠BMS. If m∠BMP = 2x + 9 and m∠BMS = 7x – 3, find the value of m∠PMS
dimulka [17.4K]

Answer:

Step-by-step explanation:

If MP bisects ∠BMS, then the line MP divides <BMS equally;

The adition postulate if therefore true;

<BMP +< PMS = <BMS and <BMP = < PMS

The equation becomes;

<BMP +< BMP= <BMS

2 <BMP = <BMS

2(2x+9) = 7x - 3

4x+18 = 7x-3

collect like terms

4x-7x = -3-18

-3x = -21

x = 21/3

x = 7

Since <BMP = < PMS 2x+9

< PMS = 2(7)+9

< PMS = 14+9

< PMS = 23

Hence the value of < PMS is 23

3 0
3 years ago
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