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ValentinkaMS [17]
3 years ago
12

Make r subject of the formula

Formula1" title="s = 4\pi \: r {}^{2} " alt="s = 4\pi \: r {}^{2} " align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
DerKrebs [107]3 years ago
4 0

Answer:

r = √( s/4π)

Step-by-step explanation:

s = 4πr²

s/4π = 4πr²/4π

r² = s/4π

√(r²) =+/-√( s/4π)

r = √( s/4π)     Because r is a radius of the circle , it should be positive.

xenn [34]3 years ago
4 0

Answer:

\boxed{r = \pm \frac{ \sqrt{s} }{2 \sqrt{\pi} } }

Step-by-step explanation:

Solve \:  for \:  r:  \\  =  > s=4\pi {r}^{2}  \\  \\ s =4\pi {r}^{2}  \:  is  \: equivalent \:  to  \: 4\pi {r}^{2}  = s:  \\  =  > 4\pi {r}^{2}  =s  \\  \\ Divide \:  both  \: sides  \: by \:  4\pi:  \\  {r}^{2}  =  \frac{s}{4\pi}  \\  \\ Take  \: the \:  square  \: root  \: of \:  both  \: sides:  \\ =  > r =  \frac{ \sqrt{s} }{2 \sqrt{\pi} }   \:  \:  \:  \: or \:  \:  \:  \:  r =   - \frac{ \sqrt{s} }{2 \sqrt{\pi} }

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