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Lynna [10]
2 years ago
9

The line passing through the points (-2,5) and (1,8)

Mathematics
1 answer:
ycow [4]2 years ago
4 0

Answer:

<u>y = x + 7</u>

Step-by-step explanation:

Calculate the slope of a line that passes through (-2,5) and (1,8).  The slope is the Rise/Run between the 2 points:

Rise = (8 - 5) or 3.

Run = (1-(-2)) = 3

Rise/Run, the slope m, is 3/3 or 1.

The equation can be written as y = 1x + b.

We need to find a value of b that forces the line though both points.  Do that by entering one of the two points into y = 1x + b and solve for b.  I'll use point (1,8)

y = x + b

8 = 1 + b

b = 7

The equation becomes <u>y = x + 7</u>

See the attached graph.

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Triangle PQR is transformed to triangle P'Q'R'. Triangle PQR has vertices P(4, 0), Q(0, −4), and R(−8, −4). Triangle P'Q'R' has
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Answer:

Please find attached the required plot accomplished with an online tool

Part A:

1/4

Part B:

P''(-1, 0),  Q''(0, -1), and R''(2, -1)

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Step-by-step explanation:

Part A:

Triangle ΔPQR has vertices P(4, 0), Q(0, -4), R(-8, -4)

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Part B:

Reflection of (x, y) across the y-axis gives;

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R'(-2, -1) image after reflection across the y-axis = R''(2, -1)

Part C:

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