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Nadya [2.5K]
3 years ago
14

Write 39/40 as a decimal

Mathematics
2 answers:
malfutka [58]3 years ago
8 0
First you divide 39/40
you would get 0.975
Studentka2010 [4]3 years ago
6 0

Answer:

Given: The fraction \frac{39}{40}

The decimal forms of rational number either end or repeat a pattern.

To convert the given  fractions to decimals you just divide the top by the bottom or divide the numerator by the denominator.

If the division does not come out, you can stop after a certain number of decimal places and round off that number.

Convert a fraction to decimal :

\frac{39}{40} =0.975

Since fraction and decimal represent the same things because numbers are not whole numbers.


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Answer:

2/3×3/5=2/3. 3/4×1/6=1/8

2/3-1/8=11/40

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Rachel is a stunt driver, and shes escaping from a building that is about to explode!
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The mean SAT score in mathematics, M, is 600. The standard deviation of these scores is 48. A special preparation course claims
kupik [55]

Answer:

Step-by-step explanation:

The mean SAT score is \mu=600, we are going to call it \mu since it's the "true" mean

The standard deviation (we are going to call it \sigma) is

\sigma=48

Next they draw a random sample of n=70 students, and they got a mean score (denoted by \bar x) of \bar x=613

The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.

- So the Null Hypothesis H_0:\bar x \geq \mu

- The alternative would be then the opposite H_0:\bar x < \mu

The test statistic for this type of test takes the form

t=\frac{| \mu -\bar x |} {\sigma/\sqrt{n}}

and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.

With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.

t=\frac{| \mu -\bar x |} {\sigma/\sqrt{n}}\\\\= \frac{| 600-613 |}{48/\sqrt(70}}\\\\= \frac{| 13 |}{48/8.367}\\\\= \frac{| 13 |}{5.737}\\\\=2.266\\

<h3>since 2.266>1.645 we  can reject the null hypothesis.</h3>
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3 years ago
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Y_Kistochka [10]

42/6 but if you want to simplify, it's 7

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At 1:00 pm the water level in a pool is 13 inches. At 1:30pm the water level is 18 inches. At 2:30pm the water level is 28 inche
SashulF [63]
From the given question we come to know of certain number of facts and they are:
At 1:00 PM the water level of the pond was = 13 inches
At 1:30 PM the water level of the pond was = 18 inches
At 2:30 PM the water level of the pond was = 28 inches
From the above given facts we can easily find the amount of water changing every half an hour.
Amount of increase in water from 1:00PM to 1:30 PM = (18 - 13) inches
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Amount of increase in water level from 1:30PM to 2:30PM = (28 -18) inches
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From the above two deductions we can come to the conclusion the the constant rate of change in water level is 5 inches for every half an hour.
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3 years ago
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