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s344n2d4d5 [400]
2 years ago
14

Solve the following simultaneous equations using an algebraic method.

Mathematics
1 answer:
Thepotemich [5.8K]2 years ago
7 0
Y = -3
x = 4

5x + 3y = 11 [1]
2x - 7y = 29. [2]

[1]*2
10x +6y = 22 [3]

[2]*5
10x - 35y = 145. [4]

[4]-[3]
-41y = 123
y = -3
sub y into 5x +3y = 11

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Mr. I does a job in x hours while Mr. L can do it in y hours. How much of the job could they do together if they were to work fo
dimulka [17.4K]

Answer: Work done by both of them in k hours is

\frac{k(x+y)}{xy}

Explanation:

Since we have given that

Number of hours Mr. I does a job = x hours

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Work done by Mr. I is given by

\frac{1}{x}

Work done by Mr. L is given by

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Work done if they do together is given by

\frac{1}{x}+\frac{1}{y}\\\\=\frac{x+y}{xy}

Work done if they work together for k hours is given by

\frac{x+y}{xy}\times k\\\\=\frac{k(x+y)}{xy}

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3 0
3 years ago
What is the answer to Factor 3a^2-6a
Anton [14]
Hi there!

3 {a}^{2}  - 6a \:  = 3a(a - 2)

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3a {}^{2}  = 3 \times \: a  \times a
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Now we can see that the terms that are in common are 3 and a, and therefore we can bring those outside the parenthesis.

7 0
3 years ago
Write the phrase as an algerbraic expression. 4 times the sum of a number and 20
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When factoring x2 – 3xy + 2y2 by grouping the first step can be:
blagie [28]

Answer:

x^2 – 3xy + 2y^2

Step-by-step explanation:

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Hint: | Factor the quadratic x^2 - 3 x y + 2 y^2.

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8 0
3 years ago
I need help!
timama [110]
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