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hammer [34]
3 years ago
6

First 2 common multiples of 8 and 9

Mathematics
2 answers:
Alik [6]3 years ago
7 0
The first two common multiples of 8 and 9 are 72 and 144!
RSB [31]3 years ago
3 0
8:0,8
9:0,9

Hope this helped
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Can someone solve this?
ladessa [460]
  • First question:

Recall that \cos^2x+\sin^2x=1 and \sqrt{x^2}=|x| for all x. So

\sqrt{1-\cos^2x}=\sqrt{\sin^2x}=|\sin x|

\sqrt{1-\sin^2x}=\sqrt{\cos^2x}=|\cos x|

For 0, we expect both \cos x>0 and \sin x>0 (i.e. the sine and cosine of any angle that lies in the first quadrant must be positive). By definition of absolute value, |x|=x if x>0.

So we have

\dfrac{\sqrt{1-\cos^2x}}{\sin x}+\dfrac{\sqrt{1-\sin^2x}}{\cos x}=\dfrac{\sin x}{\sin x}+\dfrac{\cos x}{\cos x}=1+1=\boxed{2}

making H the answer.

  • Second question:

C is always true, because the inequality reduces to x > y.

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prisoha [69]

Hello!

First, we need to find the unit rate.

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Hope this helps, ~Pooch ♥

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