Answer:
Step-by-step explanation:
A)
the sum of any two sides of a right triangle more than any other side
14+15>29, x is less than 29
14+x>15
x>1
15+x>14
x>-1
1<x<29
lets use Pythagorean Theorem
14^(2)+15^(2)=c^2
196+225=c^2
421=c^2
plusminus sqrt(421)=c
distance can't be negative, so:
c=sqrt(421)
c=20.5182845287
sqrt(421) is the largest possible right triangle side
1<x
sqrt(421)
B) as we can see from above, the largest possible length of the third side is 14/sqrt(421) or about 20.5182845287ft
C)sqrt(421) by 14 by 15
tan(x1)=15/14
x1=tan^-1(15/14)
x1=47 degrees
tan(x2)=14/15
x2=tan^-1(14/15)
x2=43 degrees
I looked it up and wrote the 14=5:2 in and this is what it said
Answer:
<u>-12x³</u>
(x⁴ +1)⁴
Step-by-step explanation:
y=1/(x^4+1)^3
y= (x⁴+1)-³
<u>dy</u><u> </u>= <u>d</u><u>(</u><u>x⁴</u><u>+</u><u>1</u><u>)</u><u>-</u><u>³</u> × <u>d</u><u>(</u><u>x</u><u>⁴</u><u>+</u><u>1</u><u>)</u>
dx d(x⁴+1) dx
=-3.(x⁴+1)-³-¹× 4x³
= -12x³(x⁴+1)-⁴
= <u>-</u><u>12</u><u>x</u><u>³</u>
(x⁴+1)⁴
Note: <u>d</u><u>x</u><u>^</u><u>n</u><u> </u> =(n. x^n-1)<u>dx</u>
dx dx
Answer:
x=1, y=2
Step-by-step explanation:
x + 7y = 15
x + 2y = 5
Subtract the two equations
x + 7y = 15
-x - 2y =- 5
------------------------
0x +5y = 10
Divide by 5
5y/5 = 10/5
y =2
Now find x
x+2y = 5
x +2(2) = 5
x +4 = 5
Subtract 4 from each side
x-4+4 = 5-4
x = 1