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dybincka [34]
3 years ago
8

Can someone solve for x please:

Mathematics
2 answers:
ehidna [41]3 years ago
4 0
Of course you could solve for x.  The LCD of these three fracgtions is (x-2)(x+2)(x).

However, you could identify the correct answer by subbing the given x values into the original equation of fractions.  For example, if you want to test out x = -4/3 and x = -5, focus on one or the other first.  If x = -4/3

then the first fraction becomes

     2
-------------     Calculate the other 2 fractions for x = -4/3.  Is the resulting 
-4/3 - 6/3      equation then true?
Alecsey [184]3 years ago
3 0
THe LCD is x(x^2 - 4)

so multiplying through by this we get:-

2x(x + 2) + 7x =  5(x^2 - 4)
2x^2 + 4x + 7x = 5x^2 - 20
3x^2 - 11x  - 20 = 0

(3x + 4)(x - 5 ) =  0

so x =  5 , -4/3

Its the second choice
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