K has the equation 2y + 3x – 5 = 0
1 answer:
Answer:
The gradient of Line L =
Step-by-step explanation:
<u><em>The equation for K is:</em></u>
=> 2y+3x-5 = 0
<u><em>Arranging it in the form of slope-intercept equation:</em></u>
=>
Since, Line L is perpendicular to Line K, The gradient of it would be the negative reciprocal of this gradient and multiplying both gives the result of -1.
So,
The gradient of Line L =
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The distance travelled from the starting point is 29 km , the bearing is 344 degree
The missing diagram is attached with the answer.
<h3>What is Bearing Angle ?</h3>It is the horizontal angle between the object and another object.
It is given that the car starts from point travels for 30km on a bearing of 145, then 10 km on a bearing of 250
(a) the distance travelled from the starting point
It can be understood from the diagram that
To determine the distance , b is to determined4
By applying Cosine rule
b² = a² +c²-2ac cos
b² = 10² +30² - 2* 30*10 cos75
b² = 100+900 -600* 0.2588
b² = 100-155.2914
b² = 844.7
b = 29 km
Therefore the distance travelled from the starting point is 29 km.
(b) the bearing of the starting point from the car.
To determine the bearing ,
angle C has to be determined
By sine rule
sin C / c = sin B / b
sin C = sin 75 * 30 / 29
sin C = 0.9970
C = sin⁻¹ 0.9970
C = 85.59 degree
angle C = α +70 degree
α = 15.59 degree
Bearing = 70 + 20 + 9 0 + 90+74 = 244 degree
To know more about Bearing
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Answer:
The equation has a maximum value with a y-coordinate of -21.
Step-by-step explanation:
Given
Required
The true statement about the extreme value
First, write out the leading coefficient
means that the function would be a downward parabola;
Downward parabola always have their vertex on top of the parabola and as such, the function has a maximum value.
The maximum value is:
Where:
So, we have:
Substitute in
<em>Hence, the maximum is -21.</em>