Question

K has the equation 2y + 3x – 5 = 0

Answer 1

Answer:

The gradient of Line L = $\frac{2}{3}$

Step-by-step explanation:

The equation for K is:

=> 2y+3x-5 = 0

Arranging it in the form of slope-intercept equation:

=> $y = -\frac{3}{2} x+\frac{5}{2}$

Since, Line L is perpendicular to Line K, The gradient of it would be the negative reciprocal of this gradient and multiplying both gives the result of -1.

So,

The gradient of Line L = $\frac{2}{3}$