Answer:
A exterior angle of a polygon is an angle outside the polygon formed by one of its sides and the extension of an adjacent side.
<u>Finding x:</u>
We know that the diagonals of a rhombus bisect its angles
So, since US is a diagonal of the given rhombus:
∠RUS = ∠TUS
10x - 23 = 3x + 19 [replacing the given values of the angles]
7x - 23 = 19 [subtracting 3x from both sides]
7x = 42 [adding 23 on both sides]
x = 6 [dividing both sides by 7]
<u>Finding ∠RUT:</u>
We can see that:
∠RUT = ∠RUS + ∠TUS
<em>Since we are given the values of ∠RUS and ∠TUS:</em>
∠RUT = (10x - 23) + (3x + 19)
∠RUT = 13x - 4
<em>We know that x = 6:</em>
∠RUT = 13(6)- 4
∠RUT = 74°
Answer:
y = -(1/2)x + 4
Step-by-step explanation:
Use the standard form on an equation: y = mx + b
A line that is perpendicular has a slope that is the opposite reciprocal of the other line. We also have a point (x, y) that is on the line, so our equation begins as..
1 = -(1/2)(6) + b We must solve for b ( -1/2 is the opposite reciprocal of 2)
1 = -3 + b
4 = b
so our equation is
y = -(1/2)x + 4
Hope this helps! Don’t mind the part I crossed off.
