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AlladinOne [14]
3 years ago
10

A spring balance attempts to drag an object across a table, but the object does not move because of the force of friction acting

on the body in an equal and opposite direction. When the forces acting upon an object are equal and opposite the object is said to be in a state of equilibrium. What are these forces called?
A) Even forces
B) Balanced forces
C) Harmonized forces
D) Unbalanced forces
Physics
2 answers:
Reil [10]3 years ago
7 0
The forces are called balanced force because the force acting apon the object are equal and the opposite object is said to be in the state of equilibrium. (Please correct me if I'm wrong)
xz_007 [3.2K]3 years ago
4 0

Answer:

b

Explanation:

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kvasek [131]

Answer: h = 0.30 m

Explanation:

A person jumping from height h would possess potential energy = m g h

which will convert completely into kinetic energy as person hits the ground. Now, the maximum energy absorbed by the person can be = 200 J

m = 67 kg

g = 9.8 m/s²

⇒ m g h = 200 J

⇒ h = 200 J / (67 kg × 9.8 m/s²) = 0.30 m

Hence, a person can land safely on both legs without breaking them from a height of 0.30 m only.

8 0
3 years ago
If you push a chair across the floor at a cibstant velocity how does the force of friction compare with the force you exert?
Roman55 [17]

-- "constant velocity"   ===>    acceleration is 0 .

-- acceleration=0   ===>   forces are balanced

-- balanced forces   ===>  (friction) + (force you exert)  =  0

                                           (friction) = -(force you exert)

                        They have equal magnitude and opposite direction. 

7 0
4 years ago
A certain helium-neon laser pointer, emitting light with a wavelength of 632 nm, has a beam with an intensity of 825 W/m2 and a
BabaBlast [244]

Answer:

N = 1.62 \times 10^{15}

Explanation:

Energy of each photon is given as

E = \frac{hc}{\lambda}

here we will have

\lambda = 632 nm

now we will have

E = \frac{(6.626\times 10^{-34})(3 \times 10^8)}{632 \times 10^{-9}}

E = 3.14 \times 10^{-19} J

now let say there is N number of photons per second

so power due to photons is

P = N(3.14 \times 10^{-19})

now intensity is given as power received per unit area

so we have

I = \frac{P}{A}

825 = \frac{N(3.14 \times 10^{-19})}{\pi (1.40 \times 10^{-3})^2}

825 = N(5.11 \times 10^{-14})

N = 1.62 \times 10^{15}

5 0
3 years ago
20.0 Ω resistor and a 2.50 μF capacitor are connected in parallel with signal generator. The signal generator produces a sinusoi
Free_Kalibri [48]

Answer:

0.15A

Explanation:

The parameters given are;

R=20.0 Ω

C= 2.50 μF

V= 3.00 V

f= 2.48×10^-3 Hz

Xc= 1/2πFc

Xc= 1/2×3.142 × 2.48×10^-3 × 2.5 ×10^-6

Xc= 25666824.1

Z= 1/√(1/R)^2 +(1/Xc)^2

Z= 1/√[(1/20)^2 +(1/25666824.1)^2]

Z= 1/√(2.5×10^-3) + (1.5×10^-15)

Z= 20 Ω

But

V=IZ

Where;

V= voltage

I= current

Z= impedance

I= V/Z

I= 3.00/20

I= 0.15A

6 0
3 years ago
Balance the following equation Fe203+HCL fecl3+H20
Arturiano [62]
Balanced equation:
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3 0
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