Answer:
A) The ball hits the ground 74.45 m far from the hitting position.
B) Maximum height of the ball = 18.57 m
Explanation:
There are two types of motion in this horizontal and vertical motion.
We have velocity = 27 m/s at 45° above the horizontal
Horizontal velocity = 27cos45 = 19.09 m/s
Vertical velocity = 27sin45 = 19.09 m/s
Time to reach maximum height,
v = u + at
0 = 19.09 - 9.81 t
t = 1.95 s
So total time of flight = 2 x 1.95 = 3.90 s
A) So the ball travels at 19.09 m/s for 3.90 seconds.
Horizontal distance traveled = 19.09 x 3.90 = 74.45 m
So the ball hits the ground 74.45 m far from the hitting position.
B) We have vertical displacement
S = ut + 0.5 at²
H = 19.09 x 1.95 - 0.5 x 9.81 x 1.95² = 18.57 m
Maximum height of the ball = 18.57 m
