Answer:
Price elasticity of demand = 0.25
Explanation:
The detailed steps and appropriate derivation is as shown in the attached file.
The requirement is to change the °F to °C scale. That is;
T(°C) = [T(°F) - 32]/1.8
Substituting;
T(°C) = [428 - 32]/1.8 = 396/1.8 = 220 °C.
Therefore, 428°F will be 220°C on Celsius scale.
Answer:
17.64 km/h
Explanation:
mass of car, m = 1000 kg
Kinetic energy of car, K = 1.2 x 10^4 J
Let the speed of car is v.
Use the formula for kinetic energy.

By substituting the values

v = 4.9 m/s
Now convert metre per second into km / h
We know that
1 km = 1000 m
1 h = 3600 second
So, 
v = 17.64 km/h
Thus, the reading of speedometer is 17.64 km/h.
Answer:
Average velocity is 0.296 m/s.
Average speed is 4.0 m/s.
Explanation:
Given:
Distance of the circular track is, 
Number of laps ran is, 
Time taken for the run is, 
Now, total distance covered in 5.4 laps = 
Also, since the path is a circle, the final position of the athlete after 5.4 laps will be 0.4 of 400 m ahead of the starting point.
Distance covered in 0.4 laps is, 
Therefore, the displacement of the athlete will be 160 m as the athlete is 160 m ahead of the starting point and displacement depends on the initial and final points only.
Now, average velocity is given as:

Average speed is the ratio of total distance covered to total time taken.
So, average speed = 
Answer:
A- series B- parallel
Explanation:
In order to measure current in a circuit, the multi-meter needs to be placed in series with the circuit while when measuring voltage, the multi-meter needs to be placed in parallel with the circuit.
It should be however noted that the same current flows in a series connected circuit and same voltage flows through loads connected in parallel. The ammeter is placed in series with the load to ensure that same value of currents is flowing in both the ammeter and loads(since same current flows in series connected circuit elements and all the amount of voltage must be made to appear on the load for the current to be measured accurately.
Voltmeter is connected in parallel to the load due to high value of current possessed by the voltmeter. The parallel connection will cause the current flowing through the voltmeter to reduce to zero so that it won't have effect (increase) on the amount of current initially on the resistor thereby measuring the exact amount of voltage on the load.