In this question, we are given a matrix, and we have to perform the given operation.
The matrix is:
![\left[\begin{array}{ccc}6&-1&|5\\1&-5&|0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%26-1%26%7C5%5C%5C1%26-5%26%7C0%5Cend%7Barray%7D%5Cright%5D)
The following operation is given:
In which 
is the element at the first line and 
is the element at the second line.
Updating the first line:
Thus, the filled matrix will be given by:
![\left[\begin{array}{ccc}0&29&|5\\1&-5&|0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%2629%26%7C5%5C%5C1%26-5%26%7C0%5Cend%7Barray%7D%5Cright%5D)
For another example where row operations are applied on a matrix, you can check brainly.com/question/18546657
Answer: 16 degrees
Step-by-step explanation:
(3x - 18) = 66
Because vertically opposite angles are equal
66 - 18 = 48
48 divided by 3 = 16
<h3>
Answer: Choice D. g(x) = 3|x-3| - 6</h3>
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Explanation:
Points are of the form (x,y), where y = f(x) since y and f(x) are outputs.
When we vertically stretch by a factor of 3, we are making the function curve 3 times more stretched out along the vertical y axis. So a general point (x,y) becomes (x,3y). Whatever the y coordinate is, we multiply by 3 to get its stretched out counterpart.
Eg: (0,-2) on f(x) moves to (0,-6) which is on g(x)
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Since y = f(x), and we're multiplying y by 3, we can say
f(x) = |x-3| - 2
3*f(x) = 3*( |x-3| - 2 )
3*f(x) = 3|x-3| + 3(-2)
3*f(x) = 3|x-3| - 6
g(x) = 3|x-3| - 6
