First let us find the length of JN
JN =JK +KN
JN = 82+105 = 187
JN=187..............(1)
UC= JN -( JH +HU+CN)
We are given :
JH= 22, HU = 96 and CN = 51
plugging all the values we get
UC = 187-( 22+96+51)
UC =187 -169
UC = 18
Answer is UC =18 ( option B)
Answer:
AB = x+ 8
Step-by-step explanation:
Given : QS=6x and CS=5x-8
From the given figure,
QS = QC + CS
We are given with QS and CS
Replace it the above equation
6x = QC + 5x -8
Solve for QC
Subtract 5x on both sides
x = QC + -8
Add 8 on both sodes
QC= x + 8
QABC is a rectangle
QC = AB
So AB = x+ 8
Answer: 80 miles
Step-by-step explanation:
Answer:
tt
Step-by-step explanation:
Answer:
A. addition property of equality
Step-by-step explanation:
hope it helps
