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3 years ago

Help show work please

Mathematics

1 answer:

pantera1 [17]3 years ago

3 0

We want to get rid of the stuff in the denomenator

gcd of the denomenator is 2x
but wait, we can get rid of the deonmenator in the numerator by multiplying by 4x

muliplty the whole thing by 4x/4x

we get $\frac{x(x^2)}{4(2)+2(x+4)}=\frac{x^3}{2x+16}$

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Kendra is buying gifts for 5 friends.

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Answer:

She could spend $18 on each for the 4 friends

Step-by-step explanation:

100-28= 72

72/4=18

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3 years ago

Is the fraction 13/8 a rational number

Talja [164]

Yes. Any number that can be written as a fraction is defined as rational.

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3 years ago

The spinner of the compass is two congruent isosceles triangles connected by their bases as shown in the diagram. The base of ea

a_sh-v [17]

Answer:

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Step-by-step explanation:

By pythagorean theorum we calculate the height:

$\sqrt{5^2-1^2}$

= $\sqrt{24}$ = height of triangle

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area = $2*\sqrt{24}$

There are two triangles so:

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Multiply this by 13.25 to get total cost:

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3 years ago

Read 2 more answers

A random sample of 20 students yielded a mean of ¯x = 72 and a variance of s2 = 16 for scores on a college placement test in mat

Helen [10]

Answer:

The 98% confidence interval for the variance in the pounds of impurities would be $8.400 \leq \sigma^2 \leq 39.827$ .

Step-by-step explanation:

1) Data given and notation

$s^2 =16$ represent the sample variance

s=4 represent the sample standard deviation

$\bar x$ represent the sample mean

n=20 the sample size

Confidence=98% or 0.98

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case the sample variance is given and for the sample deviation is just the square root of the sample variance.

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=20-1=19$

Since the Confidence is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and we can use excel, a calculator or a table to find the critical values.