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3 years ago

Write 42.5% as a decimal. (be sure to put the zero before the decimal point.)

Mathematics

1 answer:

Marrrta [24]3 years ago

4 0

Not highschool, but nice try.

42.5% can be written as 0.425

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Jacadi is setting up a tent. Each section of a tent pole is

Ghella [55]

Answer:

12 feet

Step-by-step explanation:

know that 4 sections =1 tent pole
1 yard = 3 feet
multiply the number of sections (4) by their length (3)
12 feet equal 1 tent pole
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2 years ago

Evaluate 2(L+W)<br> for L=10 and W= 2

arsen [322]

Answer:

Step-by-step explanation:

2(10+2)

turns into 2×12

so, that would be 24

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1 year ago

Can anyone answer this

erik [133]

Answer:

Step-by-step explanation:

1. 10² + 7² = x²

149 = x²

x = √149

2. x² + 19² = 21²

x² = 21² - 19² = 80

x = √80 = 4√5

3. x² + 16² = 27²

x² = 27² - 16² = 473

x = √473

4. 5.3² + 12.8² = x²

191.93 = x²

x = √191.93

5. 9² + 20² = x²

481 = x²

x = √481

6. 31 = x + 2√(19²-17²) = x + 2·6√2 = x + 12√2

x = 31 - 12√2

5 0

2 years ago

Melissa collects data on her college graduating class. She finds out that of her classmates, 60% are brunettes, 20% have blue ey

Ivahew [28]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

What is the best approximation of the projection of (5,-1) onto (2,6)?

Hatshy [7]

Answer:

Hence, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\sqrt{10} }{5}$ , and the vector projection of $\vec a$ onto $\vec b$ = $\frac{1}{5} \hat i+\frac{3}{5} \hat j$ .

Step-by-step explanation:

We have given two points $(5, -1)$ and $(2, 6)$ .

Let, $\vec a=5\hat {i}-\hat {j}$ and $\vec b= 2\hat {i}+6\hat{j}$ .

and we have calculate the projection of $\vec a$ onto $\vec b$ .

Now,

For the calculation of projection, first we need to calculate the dot product of $\vec a$ and $\vec b$ .

$\vec a.\vec b=(5\hat {i}-\hat{j}).(2\hat{i}+6\hat{j})$

$=10-6$

$=4$

then, we have to calculate the magnitude of $\vec b$ .

$\mid {\vec {b}}\mid$ = $\sqrt{2^{2}+6^{2} }$ = $\sqrt{40}$ = $2\sqrt{10}$ .

Now, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\vec a.\vec b}{\mid b\mid}$

= $\frac{4}{2\sqrt{10} }$ $\frac{2}{\sqrt{10} } \times\frac{\sqrt{10} }{\sqrt{10} } =\frac{2\sqrt{10} }{10} = \frac{\sqrt{10} }{5}$

and the vector projection of $\vec a$ onto $\vec b$ = $\frac{\vec a. \vec b}{\mid\vec b \mid^{2} } . \vec b$

= $\frac{4}{40} . (2\hat i+ 6\hat j)$

= $\frac{1}{5} \hat i+\frac{3}{5} \hat j$

Hence, the scalar projection of $\vec a$ onto $\vec b$ = $\frac{\sqrt{10} }{5}$ , and the vector projection of $\vec a$ onto $\vec b$ = $\frac{1}{5} \hat i+\frac{3}{5} \hat j$ .

6 0

3 years ago