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pshichka [43]
3 years ago
11

Multiply 5/12 and the multiplicative inverse of -1/4​

Mathematics
1 answer:
IgorC [24]3 years ago
4 0

Answer:

The answer is -2

Step-by-step explanation:

Hope it helps :)

You might be interested in
(a) Let R = {(a,b): a² + 3b <= 12, a, b € z+} be a relation defined on z+)
grin007 [14]

Answer:

R is an equivalence relation, since R is reflexive, symmetric, and transitive.

Step-by-step explanation:

The relation R is an equivalence if it is reflexive, symmetric and transitive.

The order to options required to show that R is an equivalence relation are;

((a, b), (a, b)) ∈ R since a·b = b·a

Therefore, R is reflexive

If ((a, b), (c, d)) ∈ R then a·d = b·c, which gives c·b = d·a, then ((c, d), (a, b)) ∈ R

Therefore, R is symmetric

If ((c, d), (e, f)) ∈ R, and ((a, b), (c, d)) ∈ R therefore, c·f = d·e, and a·d = b·c

Multiplying gives, a·f·c·d = b·e·c·d, which gives, a·f = b·e, then ((a, b), (e, f)) ∈R

Therefore R is transitive

From the above proofs, the relation R is reflexive, symmetric, and transitive, therefore, R is an equivalent relation.

Reasons:

Prove that the relation R is reflexive

Reflexive property is a property is the property that a number has a value that it posses (it is equal to itself)

The given relation is ((a, b), (c, d)) ∈ R if and only if a·d = b·c

By multiplication property of equality; a·b = b·a

Therefore;

((a, b), (a, b)) ∈ R

The relation, R, is reflexive.

Prove that the relation, R, is symmetric

Given that if ((a, b), (c, d)) ∈ R then we have, a·d = b·c

Therefore, c·b = d·a implies ((c, d), (a, b)) ∈ R

((a, b), (c, d)) and ((c, d), (a, b)) are symmetric.

Therefore, the relation, R, is symmetric.

Prove that R is transitive

Symbolically, transitive property is as follows; If x = y, and y = z, then x = z

From the given relation, ((a, b), (c, d)) ∈ R, then a·d = b·c

Therefore, ((c, d), (e, f)) ∈ R, then c·f = d·e

By multiplication, a·d × c·f = b·c × d·e

a·d·c·f = b·c·d·e

Therefore;

a·f·c·d = b·e·c·d

a·f = b·e

Which gives;

((a, b), (e, f)) ∈ R, therefore, the relation, R, is transitive.

Therefore;

R is an equivalence relation, since R is reflexive, symmetric, and transitive.

Based on a similar question posted online, it is required to rank the given options in the order to show that R is an equivalence relation.

Learn more about equivalent relations here:

brainly.com/question/1503196

4 0
2 years ago
Question 9 Of 1000 randomly selected cases of lung cancer, 841 resulted in death within 10 years. Construct a 95% two-sided conf
givi [52]

Answer:

0.818335 ≤ p ≤ 0.86366

Step-by-step explanation:

Given that:

Sample size (n) = 1000

Positive lung cancer = 841

n(p) = 841, p(p) = 841/1000 = 0.841

n(1 - p) = 1000 - 841 = 159

1 - p = 0.159

95% confidence interval

For a 95% confidence interval : z = 1.96

P ± z√p(1-p) / n

0.841 ± 1.96 * √0.841(0.159) / 1000

0.841 - (1.96 * 0.0115636) = 0.818335344

0.841 + (1.96 * 0.0115636) = 0.863664656

0.818335 ≤ p ≤ 0.86366

4 0
3 years ago
Question 18<br> Decrease £4600 by 20%
NISA [10]

Answer:

3680

Step-by-step explanation:

So, we would subtract. But, first we have to find the percent. But, we all use calculators so, it is 920. Saves us a lot of time.

4600 - 920 = 3680

Therefore your answer is 3680

Hope this helps!

4 0
3 years ago
70*6000 associative and commutative properties
stealth61 [152]
The commutative property of multiplication is 6000*70
8 0
3 years ago
Last question from this huge packet (more than 20 questions). Will somebody help me please. I have Science to do after this.
brilliants [131]
The correct answer is D
8 0
3 years ago
Read 2 more answers
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