Answer:
option (c) n = 201
Step-by-step explanation:
Data provided in the question:
Standard deviation, s = 5.5 ounce
Confidence level = 99%
Length of confidence interval = 2 ounces
Therefore,
margin of error, E = (Length of confidence interval ) ÷ 2
= 2 ÷ 2
= 1 ounce
Now,
E = 
here,
z = 2.58 for 99% confidence interval
n = sample size
thus,
1 = 
or
n = (2.58 × 5.5)²
or
n = 201.3561 ≈ 201
Hence,
option (c) n = 201
Answer:
45%
Step-by-step explanation:
For simplicity, let use assume there are 100 students in the school.
No. of students to complete college = (30/100) x 100 = 30 Students
President wants to increase by 50% = (50/100) x 30 = 15 Students
New set goal = 30 + 15 = 45 students.
Total number of students = 100 students
Therefore;
Rate goal % = (45/100) x 100% = 45%
Im pretty sure its 1.09375
Answer:
individual is the correct answer
Step-by-step explanation:
