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4 years ago

Round 1045 to the nearest thousand

Mathematics

1 answer:

solmaris [256]4 years ago

6 0

Hi the answer is 1,000 Glad To Help! :-D

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Matthew built 30 toys airplanes in 5 hours. What was Matthew’s unit rate for building the airplanes?

vodka [1.7K]

It would be 6 toys per hour due to the fact that 30 toys divided by 5 hours would come out to 6

4 0

4 years ago

Given h()<br> - 4x - 4, solve for a when h(x)<br> -8.

Ilia_Sergeevich [38]

Answer:

Step-by-step explanation:

this is a function

if h(x) is -8 you would plug it in for x:

-4(-8) -4 a negative × a negative is a positive

32- 4= 28

7 0

3 years ago

Read 2 more answers

Distribution with a mean of 100 and standard deviation of 15...

anzhelika [568]

Use the z-score:
112 - 100
For 112, the z-score is --------------- = 12/15, or 0.8.
15

Next, find the AREA under the standard normal curve TO THE LEFT OF 0.8.

Use either a z-score table or a calculator for this purpose.

Using my calculator, I found that this area is 0.532. That places 112 in the 53rd percentile.

82 would be in a lower percentile: the 12th percentile.

Let me know if you have questions about how to use a calculator to do these calculations.

8 0

4 years ago

Help with this question??

Reika [66]

Answer:

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

$\frac{f(b)-f(a)}{b-a}$

here [ a, b ] = [ 0, 2 ] and from the graph

f(b) = f(2) = 0

f(a) = f(0) = - 6, hence

average rate of change = $\frac{0-(-6)}{2-0}$ = $\frac{6}{2}$ = 3

3 0

4 years ago

Suppose that in a senior college class of 500500 students, it is found that 179179 smoke, 228228 drink alcoholic beverages, 1

olga2289 [7]

Answer: a) 0.16, b) 0.058, and c) 0.856.

Step-by-step explanation:

Since we have given that

Number of students = 500

Number of students smoke = 179

Number of students drink alcohol = 228

Number of students eat between meals = 119

Number of students eat between meals and drink alcohol = 59

Number of students eat between meals and smoke = 72

Number of students engage in all three = 30

a) Probability that the student smokes but does not drink alcohol is given by

$P(S-A)=P(S)-P(S\cap A)\\\\P(S-A)=\dfrac{179}{500}-\dfrac{99}{500}\\\\P(S-A)=\dfrac{179-99}{500}\\\\P(S-A)=\dfrac{80}{500}\\\\P(S-A)=0.16$

b) eats between meals and drink alcohol but does not smoke.

$P((M\cap A)-S)=P(M\cap A)-P(M\cap S\cap A)\\\\P((M\cap A)-S)=\dfrac{59}{500}-\dfrac{30}{500}\\\\P((M\cap A)-S)=\dfrac{59-30}{500}\\\\P((M\cap A)-S)=\dfrac{29}{500}\\\\P((M\cap A)-S)=0.058$

c) neither smokes nor eats between meals.

$P(S'\cap M')=1-P(S\cup M)\\\\P(S'\cap M')=1-\dfrac{72}{500}\\\\P(S'\cap M')=\dfrac{500-72}{500}\\\\P(S'\cap M')=\dfrac{428}{500}=0.856$

Hence, a) 0.16, b) 0.058, and c) 0.856.

5 0

3 years ago