*the diagram of the Russian stringed instrument is attached below.
Answer/Step-by-step explanation:
To show that the traingular parts of the two balalaikas instruments are congruent, substitute x = 6, to find the missing measurements that is given in both ∆s.
Parts of the first ∆:
WY = (2x - 2) in = 2(6) - 2 = 12 - 2 = 10 in
m<Y = 9x = 9(6) = 54°.
XY = 12 in
Parts of the second ∆:
m<F = 72°
HG = (x + 6) in = 6 + 6 = 12 in
HF = 10 in
m<G = 54°
m<H = 180 - (72° + 54°)
m<H = 180 - 126
m<H = 54°
From the information we have, let's match the parts that are congruent to each other in both ∆s:
WY ≅ FH (both are 10 in)
XY ≅ GH (both are 12 in)
<Y ≅ <G (both are 54°)
Thus, since two sides (WY and XY) and an included angle (<Y) of ∆WXY is congruent to two corresponding sides (FH and GH) and an included angle (<G) in ∆FGH, therefore, ∆WXY ≅ ∆FGH by the Side-Angle-Side (SAS) Congruence Theorem.
This is enough proof to show that the triangular parts of the two balalaikas are congruent for x = 6.
Answer:
243
Step-by-step explanation:
3^2 x 3^3 is the same as 3x3 x 3x3x3 which is 9x27 which is 243
Apply the cosine double angle identity to get:
Cos 2PI/3
Answer:
10/3 or 3 1/3
Step-by-step explanation:
Ⓗⓘ ⓣⓗⓔⓡⓔ
0.5(n-4)-3=3-(n+3)
First, you would do the distributive property:
0.5n-2-3=3-n-3
Then you would simplify and then solve.
0.5n-5=-n
-5=-1.5n
n=5/1.5
n=10/3 or 3 1/3
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For the equation y - x < 0,
y < x
The shaded portion will be under the dashed line joining points (-2, -2) and (3, 3).
for the equation x - 1 > 0,
x > 1
The shaded portion will be to the right of the dashed line joining points (1, 5) and (1, -3).
The portion affected by the two shadings will be the portion common to the right of the dashed line joining points (1, 5) and (1, -3) and under the dashed line joining points (-2, -2) and (3, 3).
Therefore the correct answer is option c.