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Fittoniya [83]
4 years ago
10

Math scores on the SAT exam are normally distributed with a mean of 514 and a standard deviation of 118. If a recent test-taker

is selected at random, what is the probability the student scored between 455 and 573 on the exam?
Mathematics
1 answer:
LuckyWell [14K]4 years ago
7 0

Answer:

Probability that the student scored between 455 and 573 on the exam is 0.38292.

Step-by-step explanation:

We are given that Math scores on the SAT exam are normally distributed with a mean of 514 and a standard deviation of 118.

<u><em>Let X = Math scores on the SAT exam</em></u>

So, X ~ Normal(\mu=514,\sigma^{2} =118^{2})

The z score probability distribution for normal distribution is given by;

                              Z  =  \frac{X-\mu}{\sigma} ~  N(0,1)

where, \mu = population mean score = 514

           \sigma = standard deviation = 118

Now, the probability that the student scored between 455 and 573 on the exam is given by = P(455 < X < 573)

       P(455 < X < 573) = P(X < 573) - P(X \leq 455)

       P(X < 573) = P( \frac{X-\mu}{\sigma} < \frac{573-514}{118} ) = P(Z < 0.50) = 0.69146

       P(X \leq 2.9) = P( \frac{X-\mu}{\sigma} \leq \frac{455-514}{118} ) = P(Z \leq -0.50) = 1 - P(Z < 0.50)

                                                         = 1 - 0.69146 = 0.30854

<em>The above probability is calculated by looking at the value of x = 0.50 in the z table which has an area of 0.69146.</em>

Therefore, P(455 < X < 573) = 0.69146 - 0.30854 = <u>0.38292</u>

Hence, probability that the student scored between 455 and 573 on the exam is 0.38292.

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A coin is tossed 5 times. Find the probability that exactly 1 is a tail. Find the probability that at most 2 are tails.
Natalija [7]

Answer:

Step-by-step explanation:

<h2>First question</h2>

The only possibilities where there is exactly 1 tail are:

  1. (t,h,h,h,h)
  2. (h,t,h,h,h)
  3. (h,h,t,h,h)
  4. (h,h,h,t,h)
  5. (h,h,h,h,t)

those are 5 favorable outcomes.

where <em>h represent heads</em> and <em>t represent tails. </em>There are 2^5 32 total number of outcomes after tossing the coin 5 times. Because every time you toss the coin, you have 2 possibilities, and as you do it 5 times, those are 2^5 options. We can conclude from this that

The probability that exactly 1 is a tail is 5/32.

<h2>Second question</h2>

We already know the total number of outcomes; 32.  Now we need to find the number of favorable outcomes. In order to do that, we can divide our search in three cases: <em>1.-there are no tails, 2.-exactly 1 is a tail, 3.- exactly 2 are tails.</em>

The first case is 1 when every coin is a head. The second case we already solved it, and there are 5. The third case is the interesting one, we can count the outcomes as we did in the previous questions, but that's only because there are not too many outcomes.  Instead we are going to use combinations:

We need to have <u>2</u> tails, the other coins are going to be heads. We made <u>5</u> tosses, then the possible combinations are C_{5,2} = \frac{5!}{3!2!} = \frac{120}{6*2} = 10

Finally, we conclude that there are 1 + 5 + 10 favorable outcomes, and this implies that

The probability that at most 2 are tails is \frac{16}{32} = \frac{1}{2}.

4 0
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Mariulka [41]

Answer:

\frac{8}{11}

Step-by-step explanation:

Since the fractions are like, their denominators are 11, then

consider the values that sum to give 18 , that is

1 + 9 + ? = 18

10 + ? = 18 ( subtract 10 from both sides )

? = 8

Then the third fraction is \frac{8}{11}

5 0
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This rectangular prism was built with cubes that each have a volume of one cubic centimeter.
vfiekz [6]

Answer:

The volume of this rectangular prism is 60.

Step-by-step explanation:

V = L*W*H

( For a rectangular prism )

4 * 5 * 3

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3 years ago
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Answer:

c)41

Step-by-step explanation:

∠DBE = (∠ABE +∠DBC) -∠ABC

          = (74 + 103)  -136

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Answer:

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Step-by-step explanation:

(x^2-x-2)/(x-2)=(x+1)

Because (x-2)(x+1)=x^2-2x+x-2=x^2-x-2.

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