Answer: the cost of one chicken is $8
The cost of one duck is $5
Step-by-step explanation:
Let x represent the cost of one chicken.
Let y represent the cost of one duck.
Last month, he sold 50 chickens and 30 ducks for $550. It means that
50x + 30y = 550- - - - - - - - - - - 1
This month, he sold 44 chickens and 36 ducks for $532. It means that
44x + 36y = 532- - - - - - - - - - - 2
Multiplying equation 1 by 44 and equation 2 by 50, it becomes
2200x + 1320y = 24200
2200x + 1800y = 26600
Subtracting, it becomes
- 480y = - 2400
y = - 2400/- 480
y = 5
Substituting y = 5 Intl equation 1, it becomes
50x + 30 × 5 = 550
50x + 150 = 550
50x = 550 - 150
50x = 400
x = 400/50
x = 8
3750(0.20)=$750
1/5 as a percent is 20% and as a fraction it is 0.20
Step-by-step explanation:
t1 = 1 = 7*1 - 6
t2 = 8 = 7* 2 - 6
t3 = 15 = 7 * 3 - 6
t4 = 22 = 7 *4 - 6
t5 = 29 = 7 * 5 - 6
-------------------------
Tn = 7n - 6
Answer:
(a) The sample sizes are 6787.
(b) The sample sizes are 6666.
Step-by-step explanation:
(a)
The information provided is:
Confidence level = 98%
MOE = 0.02
n₁ = n₂ = n
Compute the sample sizes as follows:
Thus, the sample sizes are 6787.
(b)
Now it is provided that:
Compute the sample size as follows:
![n=\frac{(z_{\alpha/2})^{2}\times [\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})]}{MOE^{2}}](https://tex.z-dn.net/?f=n%3D%5Cfrac%7B%28z_%7B%5Calpha%2F2%7D%29%5E%7B2%7D%5Ctimes%20%5B%5Chat%20p_%7B1%7D%281-%5Chat%20p_%7B1%7D%29%2B%5Chat%20p_%7B2%7D%281-%5Chat%20p_%7B2%7D%29%5D%7D%7BMOE%5E%7B2%7D%7D)
![=\frac{2.33^{2}\times [0.45(1-0.45)+0.58(1-0.58)]}{0.02^{2}}\\\\=6665.331975\\\\\approx 6666](https://tex.z-dn.net/?f=%3D%5Cfrac%7B2.33%5E%7B2%7D%5Ctimes%20%5B0.45%281-0.45%29%2B0.58%281-0.58%29%5D%7D%7B0.02%5E%7B2%7D%7D%5C%5C%5C%5C%3D6665.331975%5C%5C%5C%5C%5Capprox%206666)
Thus, the sample sizes are 6666.
Answer: X=1
Step-by-step explanation:
The hypotenuse is √2 which means that x²+x²=(√2)² using Pythagoras
Simplify and solve
2x²=2
x²=1
X=√1
X=1
