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baherus [9]
3 years ago
11

Jennifer has 4/5 as many oictures on her camera as luisa does. Jennifer has 28 pictures on her camera. How many pictures do Jenn

ifer and Luisa have in all?
Mathematics
1 answer:
spayn [35]3 years ago
8 0
Answer=63 pictures

Jennifer=4/5*Luisa

Jennifer=28
Substitute '28' for Jennifer

28=4/5*Luisa
divide both sides by 4/5
35=Luisa

Luisa has 35 pictures on her camera

35+28=63
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PLEASE HELP WITH THIS PLEASE!!
Nonamiya [84]

Answer:

96

Step-by-step explanation:

this is the answer I think

7 0
2 years ago
Read 2 more answers
Give a geometric description of the following system of equations.a. 2x−4y=12 −3x+6y=−15.b. 2x−4y=12 −5x+3y=10.a. 2x−4y=12 −3x+6
Reptile [31]

Answer:

a. No solution, parallel lines.

b. One solution.

Step-by-step explanation:

Given the system of equations:

a. 2x-4y=12

-3x+6y=-15

b. 2x-4y=12

-5x+3y=10

To give a geometric description of the given system of equations.

The geometric description of a system of equations in 2 variables mean the system of equations will represent the number of lines equal to the number of equations in the system given.

i.e.

Number of planes = Number of variables

Number of lines = Number of equations in the system.

Here, we are given 2 variables and 2 equation in each system.

So, they can be represented in the xy-coordinates plane.

And the number of solutions to the system depends on the following condition.

Let the system of equations be:

A_1x+B_1y+C_1=0\\A_2x+B_2y+C_2=0

1. One solution:

There will be one solution to the system of equations,  If we have:

\dfrac{A_1}{A_2}\neq\dfrac{B_1}{B_2}

2. Infinitely Many Solutions: (Identical lines in the system)

\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}= \dfrac{C_1}{C_2}

3. No Solution:(Parallel lines)

\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}\neq\dfrac{C_1}{C_2}

Now, let us discuss the system of equations one by one:

a. 2x-4y=12 OR 2x-4y-12=0

-3x+6y=-15 OR -3x+6y+15=0

A_1 = 2, B_1 = -4, C_1 = -12\\A_2 = -3, B_2 = 6, C_2= 15

Here, the ratio:

\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2} = -\dfrac{2}{3}\\\dfrac{C_1}{C_2} = -\dfrac{4}{5}

\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}\neq\dfrac{C_1}{C_2}

Therefore, no solution i.e. parallel lines.

b. 2x-4y=12 OR 2x-4y-12=0

-5x+3y=10 OR -5x+3y-10=0

A_1 = 2, B_1 = -4, C_1 = -12\\A_2 = -5, B_2 = 3, C_2 = -10

\dfrac{A_1}{A_2}= -\dfrac{2}{5}\\\dfrac{B_1}{B_2} = -\dfrac{4}{3}\\\dfrac{C_1}{C_2} = -\dfrac{6}{5}

\dfrac{A_1}{A_2}\neq\dfrac{B_1}{B_2}

So, one solution.

Kindly refer to the images attached for the graphical representation of the given system of equations.

6 0
2 years ago
You have just opened a new dance club, Swing Haven, but are unsure of how high to set the cover charge (entrance fee). One week
bonufazy [111]

Answer:

a) The demand function is

q(p) = -4 p + 107

b) The nightly revenue is

R(p) = -4 p^2 + 107 p

c) The profit function is

P(p) = -4 p^2 + 133.75 p - 939

d) The entrance fees that allow Swing Haven to break even are between 10.03 and 23.41 dollars per guest.

Step-by-step explanation:

a) Lets find the slope s of the demand:

s = \frac{79-43}{7-16} = \frac{36}{-9} = -4

Since the demand takes the value 79 in 7, then

q(p) = -4 (p-7) + 79 = -4 p + 107

b) The nightly revenue can be found by multiplying q by p

R(p) = p*q(p) = p*( -4 p + 107) = -4 p^2 + 107 p

c) The profit function is obtained from substracting the const function C(p) from the revenue function R(p)

P(p) = R(p) - C(p) = p*q(p) = -4 p^2 + 107 p - (-26.75p + 939) = \\\\-4 p^2 + 133.75 p - 939

d) Lets find out the zeros and positive interval of P. Since P is a quadratic function with negative main coefficient, then it should have a maximum at the vertex, and between the roots (if any), the function should be positive. Therefore, we just need to find the zeros of P

r_1, r_2 = \frac{-133.75 \,^+_-\, \sqrt{133.75^2-4*(-4)*(-939)} }{-8} = \frac{-133.75 \,^+_-\, 53.526}{-8} \\r_1 = 10.03\\r_2 = 23.41

Therefore, the entrance fees that allow Swing Haven to break even are between 10.03 and 23.41 dollars per guest.

7 0
3 years ago
What is the value of fraction 1 over 3x3 + 5.2y when x = 3 and y = 2?
Slav-nsk [51]

Hello from MrBillDoesMath!

Answer:

1/ 91.4

Discussion:

Evaluate  1/ ( 3x^3 + 5.2y)   when x = 3, y = 2.

1/ (3 (3)^3 + 5.2(2))  =

1/ ( 3 * 27 + 10.4) =

1/ ( 81 + 10.4) =

1/ (91.4) =

.0109 (approx)

Thank you,

MrB

6 0
3 years ago
Please help I don't get number five and please explain
marysya [2.9K]
The answer is 11 becauze the pattern works like this - 18÷2=9 20÷2=10 22÷2=11 Basically the X axis being divided by 2 which equals the Y axis (eg: X÷2=Y
3 0
3 years ago
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