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Daniel [21]
3 years ago
5

Express the ratio below in its simplest form. 1 3 : 1 2

Mathematics
1 answer:
ra1l [238]3 years ago
3 0
You can write any ratio as a fraction so 1/3:1/2 can be re-written as \frac{1/3}{1/2} so you need to simplify the complex fraction to find the ratio
\frac{1}{3} *  \frac{2}{1} - Invert the denominator and multiply to find the ratio
2/3 - the answer
2:3 - convert back to a ratio
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The red square is the image of the blue square after a SINGLE transformation. Use two or more complete sentences to describe eac
Leni [432]

The transformations which can lead to the red square image of the blue Square are; Translation, Reflection, Rotation.

<h3>What transformations lead to the image?</h3>

  • Translation is when we slide a figure in any direction. The translation of the shape can be by moving the blue leftward or rightward and the then downward.
  • Reflection is when we flip a figure over a line. The reflection involves reflect the blue Square over the line; y = x.
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Read more on transformations;

brainly.com/question/4289712

5 0
2 years ago
What is the area of a regular heptagon with side length of 6 meters and a distance from the to the vertex of 6 meters? round you
Ahat [919]
Apothem = side length / 2*tan(180 / number of sides)
apothem = side length / 2*tan (180 / 7)
apothem = 6 / (2*tan( <span> <span> <span> 25.7142857143</span></span></span>))
apothem = 6 / 2*0.48157
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Polygon area = (# of sides * side length * apothem) / 2
Polygon area = ( 7 * 6 * <span>6.2296239384) / 2
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8 0
3 years ago
Solve the linear equations by graphing
8_murik_8 [283]

Answer:

Show a photo

Step-by-step explanation:

8 0
3 years ago
Which linear function represents the line given by the point-slope equation y – 2 = 4(x – 3)?
posledela
<span> y – 2 = 4(x – 3)

y - 2 = 4x - 12

y - 2 = 4x - 12

y = 4x - 12 + 2

y = 4x - 10

y - 4x = -10</span>
6 0
3 years ago
Read 2 more answers
The position function of a particle moving along a coordinate line is given, wheresis in feet andtis in seconds.
Sati [7]

Answer:

a) s = (4-t)/(t^2+4)^2,   a(t) = (2t^3-24t)/(t^2+4)^3

b) s = 0.2ft, v = 0.12 ft/s,  a = -0.176 ft/s^2

c) t = 2s

d) slowing down for t < 2, speeding up for t > 2

e) 0.327 ft

Step-by-step explanation:

The position function of a particle is given by:

s(t)=\frac{t}{t^2+4},\ \ \ t\geq  0   (1)

a) The velocity function is the derivative, in time, of the position function:

v(t)=\frac{ds}{dt}=\frac{(1)(t^2+4)-t(2t)}{(t^2+4)^2}=\frac{4-t^2}{(t^2+4)^2}   (2)

The acceleration is the derivative of the velocity:

a(t)=\frac{dv}{dt}=\frac{(-2t)(t^2+4t)^2-(4-t^2)2(t^2+4)(2t)}{(t^2+4)^4}\\\\a(t)=\frac{(-2t)(t^2+4)-4t(4-t^2)}{(t^2+4)^3}=\frac{2t^3-24t}{(t^2+4)^3} (3)

b) For t = 1 you have:

s(1)=\frac{1}{1+4}=0.2\ ft\\\\v(1)=\frac{4-1}{(1+4)^2}=0.12\frac{ft}{s}\\\\a(1)=\frac{2-24}{(1+4)^3}=-0.176\frac{ft}{s^2}

c) The particle stops for v(t)=0. Then you equal equation (2) to zero ans solve the equation for t:

v(t)=\frac{4-t^2}{(t^2+4)^2}=0\\\\4-t^2=0\\\\t=2

For t = 2s the particle stops.

d) The second derivative evaluated in t=2 give us the concavity of the position function.

\frac{d^2s}{dt^2}=a(2)=\frac{2(2)^3-24(2)}{(2^2+4)^3}=-0.062

Then, the concavity of the position function is negative. For t=2 there is a maximum. Before t=2 the particle is slowing down and after t=2 the particle is speeding up.

e) Due to particle goes and come back. You first calculate s for t=2, then calculate for t=5.

s(2)=\frac{2}{2^2+4}=0.25\ ft

s(5)=\frac{5}{5^2+4}=0.172\ ft

The particle travels 0.25 in the first 2 seconds. In the following three second the particle comes back to the 0.172\ ft. Then, in the second trajectory the particle travels:

0.25 - 0.127 = 0.077 ft

The total distance is the sum of the distance of the two trajectories:

s_total = 0.25 ft + 0.077 ft = 0.327 ft

6 0
3 years ago
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