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vfiekz [6]
3 years ago
6

The ratio of adams height to sam's height is 4:3 how many times sam's height is adams height

Mathematics
2 answers:
Gre4nikov [31]3 years ago
8 0
Hello there.

The ratio of adams height to sam's height is 4:3 how many times sam's height is adams height
4 / 3 = adam's height / sam's height
sam's height = (3/4) adam's height

Levart [38]3 years ago
4 0
The <span>ratio of adam's height to sam's height is 4:3. Therefore, Sam's height is 3/4 of adam's height. This is done by applying rules on ratios. We do as follows:

4 / 3 = adam's height / sam's height
sam's height = (3/4) adam's height

Hope this answers the question. Have a nice day.</span>
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mr_godi [17]

Answer:

\boxed{\sf \ \ \ 248 \ \ \ }

Step-by-step explanation:

Hello,

(fog)(4)=f(g(4)) \ \ \ and \ \ \ g(4)=-6*4^2+9*4+9=-51 \ \ so\\(fog)(4)=f(-51)=-5*(-51)-7=255-7=248

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3 years ago
Assume that it costs Apple approximately E(x) 25,600 + 100x + 0.012 dollars to manufacture x 32GB iPods in a day. (a) The averag
uranmaximum [27]

Answer:

(a)C'(x)=\dfrac{x^2-2560000}{x^2}

(b)x=1600, Minimum Average Cost Per iPod=$132

(c)C''(x)=\dfrac{5120000}{x^3}

The result, C''(1600) is positive, which means that the average cost is Concave up at the critical point, and the critical point is a minimum.

Step-by-step explanation:

Given that it costs Apple approximately $ C(x) to manufacture x 32GB iPods in a day, where:

C(x)=25,600+100x+0.01x^2

(a)The average cost per iPod when they manufacture x iPods in a day is given by:

Cost \:Per \:iPod=\dfrac{C(x)}{x} =\dfrac{25,600+100x+0.01x^2}{x}

The average cost per iPod is therefore:

C'(x)=\dfrac{x^2-2560000}{x^2}

(b)To minimize average cost of x iPods per day, we set the average cost per iPod=0 and solve for x.

C'(x)=\dfrac{x^2-2560000}{x^2}=0\\x^2-2560000=0\\x^2=2560000\\x=\sqrt{2560000}=1600

The resulting minimum average cost (at x=1600) is given as:

Cost \:Per \:iPod=\dfrac{C(x)}{x} =\dfrac{25,600+100x+0.01x^2}{x}\\\dfrac{25,600+100(1600)+0.01(1600)^2}{1600}\\=\$132

<u>Second derivative test</u>

(c)The answer above is a critical point for the average cost function. To show it is a minimum, we calculate the second derivative of the average cost function.

C''(x)=\dfrac{5120000}{x^3}

At the critical point,  x=1600

C''(1600)=\dfrac{5120000}{1600^3}=0.00125

The result, C''(1600) is positive, which means that the average cost is Concave up at the critical point, and the critical point is a minimum.

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The answer is 13z - 18
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