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german
4 years ago
11

Mrs bennet graded 20% of her 150 students papers how many papers does she have left to grade

Mathematics
1 answer:
Lerok [7]4 years ago
5 0
x-\ left\ papers\\\\
x=150-20\%*150=150-0,2*150=0,8*150=120\\\\
The\ remaining \ students' \ papers\ are\ equal\ to\ 120.

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There are 52 weeks in a year. Ben has lived in london for two fifths of year. How many weeks has ben lived in london?
masha68 [24]

Answer:

\frac{104}{5} weeks or 20\frac{4}{5} weeks

Step-by-step explanation:

To do this we can set up a proportion

\frac{52}{1} *\frac{2}{5}

This will tell us how many weeks are in 2/5 of a year

Let's evaluate this

\frac{104}{5}

We cannot simplifiy this anymore, so we will leave it as an improper fraction, or a mixed number as shown below

20\frac{4}{5} weeks

5 0
3 years ago
Read 2 more answers
Ella has gold,silver,and copper wire for stringing beads.she has1 1\2ft.of gold wire,2 1\3ft.of silver wire,and3 3\4ft.of copper
Oksana_A [137]
Ella would have 65/8ft wire all together.
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3 years ago
The diagram shows squares arranged around the edge of a right triangle. What is the area of square B
Lina20 [59]

Step-by-step explanation:

take the right triangle

15^2 = 9^2 + x^2

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6 0
3 years ago
Intellectual development (Perry) scores were determined for 21 students in a first-year, project-based design course. (Recall th
Anit [1.1K]

Answer:

The 99% confidence interval is (3.0493, 3.4907).

We are 99% sure that the true mean of the students Perry score is in the above interval.

Step-by-step explanation:

Our sample size is 21.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

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Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 20 and 0.005 in the two-sided t-distribution table, we have T = 2.528

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{0.40}{\sqrt{21}} = 0.0873

Now, we multiply T and s

M = 2.528*0.0873 = 0.2207

Then

The lower end of the interval is the mean subtracted by M. So:

L = 3.27 - 0.2207 = 3.0493

The upper end of the interval is the mean added to M. So:

LCL = 3.27 + 0.2207 = 3.4907

The 99% confidence interval is (3.0493, 3.4907).

Interpretation:

We are 99% sure that the true mean of the students Perry score is in the above interval.

7 0
3 years ago
13/10+2/100=?/100 do you guys know what it os
Mila [183]

Answer:

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Step-by-step explanation:

13/10+2/100=?/100

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132/100   = ? /100

4 0
3 years ago
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